php - Laravel 或哪里

Question

目前我正在 Laravel 中做一个项目，但我被卡住了。我想创建一个这样的 SQL 语句:

SELECT * FROM SPITems WHERE publisher_id=? AND feed_id=? AND (title LIKE '%?%' OR description LIKE '%?%')

现在我有这段代码:

$query = SPItem::orderBy('title');
if(isset($_GET['publisherID']) && is_numeric($_GET['publisherID']))
{
    $query = $query->where('publisher_id', $_GET['publisherID']);
}
if(isset($_GET['productFeedID']) && is_numeric($_GET['productFeedID']))
{
    $query = $query->where('program_id', $_GET['feedID']);
}
if(isset($_GET['search']))
{
    $query = $query->orWhere('title', 'like', '%' . $_GET['search'] . '%');
    $query = $query->where('description', 'like', '%' . $_GET['search'] . '%');
}

但这会产生:

SELECT * FROM SPITems WHERE (publisher_id=? AND feed_id=?) OR (title LIKE '%?%') AND description LIKE '%?%'

如何获得正确的“或”顺序？

Answer 1

查看文档中的逻辑分组部分:

https://laravel.com/docs/master/queries#logical-grouping

它解释了如何在 WHERE 子句中对条件进行分组。

应该是这样的:

if(isset($_GET['search']))
{
    $query->where(function($query){
        $query->where('title', 'like', '%' . $_GET['search'] . '%')
              ->orWhere('description', 'like', '%' . $_GET['search'] . '%');
    });
}