php - 如何在 paginationControl 中指定带有参数的路由？

Question

我正在尝试在我的新闻提要上创建分页。我的新闻提要有两种模式:所有新闻提要和按类别提要。所有新闻提要的分页工作正常，但我在“按类别提要”分页时遇到问题。

我这样使用 paginationControl:

<?=$this->paginationControl(
    $this->news,
    'Sliding',
    'pagination_control',
    array('route' => 'news/category')
)?>

路由 news/category 配置:

'category' => array(
    'type' => 'Segment',
    'options' => array(
        'route' => '/:category[/page-:page]',
        'constraints' => array(
            'category'     => '[a-z]+',
            'page'     => '[1-9][0-9]*',
        ),
        'defaults' => array(
            'controller' => 'News\Controller\Item',
            'action'     => 'category',
            'page'      => 1,
        )
    ),
    'may_terminate' => true,
),

所以我需要指定参数类别。我正在尝试这个:

<?=$this->paginationControl(                                                                 
    $this->news,                                                                             
    'Sliding',                                                                               
    'pagination_control',                                                                    
    array('route' => 'news/category', array('category' => $this->category->getUrl()))        
)?>          

但我收到错误“缺少参数...”:

貌似无法通过paginationControl设置参数。

如何在paginationControl中正确指定带参数的路由？

更新1

我的 paginationControl View 如下所示:

<?php if ($this->pageCount > 1): ?>
    <div>
        <ul class="pagination pagination-sm">
            <!-- Previous page link -->
            <?php if (isset($this->previous)): ?>
                <li>
                    <a href="<?=$this->url($this->route, array('page' => $this->previous))?>">
                        &laquo;
                    </a>
                </li>
            <? else: ?>
                <li class="disabled"><span>&laquo;</span></li>
            <? endif; ?>

            <!-- Numbered page links -->
            <? foreach ($this->pagesInRange as $page): ?>
                <? if ($page != $this->current): ?>
                    <li>
                        <a href="<?=$this->url($this->route, array('page' => $page))?>">
                            <?=$page?>
                        </a>
                    </li>
                <? else: ?>
                    <li class="active"><span><?=$page?></span></li>
                <? endif; ?>
            <? endforeach; ?>

            <!-- Next page link -->
            <?php if (isset($this->next)): ?>
                <li>
                    <a href="<?=$this->url($this->route, array('page' => $this->next))?>">
                        &raquo;
                    </a>
                </li>
            <?php else: ?>
                <li class="disabled"><span>&raquo;</span></li>
            <?php endif; ?>
        </ul>
    </div>
    <div>
        <span class="small grey"><?="Страница ".$this->current." из ".$this->pageCount?></span>
    </div>
<?php endif; ?>

Answer 1

您应该像@rianattow 所说的那样在末尾将所有附加参数作为关联数组传递。这样，所有这些参数都可以通过 $this->paramname

在 pagination_control.phtml 部分访问

例子:

echo $this->paginationControl(                                                                 
     $this->news,                                                                             
     'Sliding',                                                                               
     'pagination_control',                                                                    
     array( 'route' => 'news/category', 'category' => 'banana')
    );

此详细信息在 paginator documentation 中说明:

The fourth and final parameter is reserved for an optional associative array of additional variables that you want available in your view (available via $this). For instance, these values could include extra URL parameters for pagination link.

我认为另一个遗漏点是使用路由名称构建 URL。不要将 url 作为参数传递给 paginationControl() 帮助程序，而是尝试在分页部分内生成 url，如下所示:

<a href="<?
    echo $this->url($this->route, array('page' => $page, 'category' => $this->category))
?>">

希望对您有所帮助。