php - Laravel 尝试对 API JSON 响应进行单元测试

Question

试图在这里一次学习太多新东西(Laravel、PHPUnit 等)，所以这可能只是一个大脑疲惫的问题，仍然希望得到一些帮助。

我有一个非常基本的“博客”项目，使用 Laravel 作为 API 层，使用 AngularJS 作为前端。我想对 API 端点进行单元测试，但在我的测试函数中无法弄清楚如何处理 JSON。

当我尝试运行 testGetBlogPosts() 时，我在 CLI 中看到了类似 JSON 的输出，但我无法执行 json_decode() 并检查对象的某些部分是否符合我的预期结果。在这里，我只是想确保结果数组中第一个对象的 ID 是 ID“1”。

我收到的测试结果是:1) 示例测试::testGetBlogPostsErrorException:试图获取非对象的属性

非常感谢任何帮助或建议!

TL;DR:测试用例未正确处理来自 API 端点的 JSON 响应

Controller

class HomeController extends BaseController {

    /*
    |--------------------------------------------------------------------------
    | Default Home Controller
    |--------------------------------------------------------------------------
    |
    | You may wish to use controllers instead of, or in addition to, Closure
    | based routes. That's great! Here is an example controller method to
    | get you started. To route to this controller, just add the route:
    |
    |   Route::get('/', 'HomeController@showWelcome');
    |
    */
    public function showWelcome()
    {
        return View::make('hello');
    }

    public function getBlogPosts()
    {
        $posts = Post::get()->take(5)->toJson();
        // echo $posts; PER THE ACCEPTED ANSWER, RETURN NOT ECHO
        return $posts;
    }
    public function getSinglePost($postId)
    {
        $posts = Post::find($postId)->toJson();
        // echo $posts; PER THE ACCEPTED ANSWER, RETURN NOT ECHO
        return $posts;
    }

}

测试文件

class ExampleTest extends TestCase {

    /**
     * A basic functional test example.
     *
     * @return void
     */
    public function testBasicExample()
    {
        $crawler = $this->client->request('GET', '/');
        $this->assertTrue($this->client->getResponse()->isOk());
    }

    public function testGetBlogPosts()
    {
        $response = $this->call('GET', 'api/getBlogPosts');

        $array = json_decode($response);
        $result = false;
        if($array[0]->id == 1)
        {
            $result = true;
        }
        $this->assertEquals(true, $result);
    }
}

应要求，完整的测试输出

root@homestead:/home/vagrant/Laravel/Homestead/Blog# phpunit PHPUnit 3.7.28 by Sebastian Bergmann.

Configuration read from /home/vagrant/Laravel/Homestead/Blog/phpunit.xml

.E[{"id":"1","user_id":"1","title":"This is a test post","post_body":"testststs","created_at":"2014-08-07 19:26:26","updated_at":"2014-08-07 19:26:26"},{"id":"2","user_id":"75","title":"Libero rerum rem praesentium et et at doloribus asperiores.","post_body":"Commodi aut beatae aut veritatis eum soluta sint. In aut cumque iure quis.","created_at":"2014-08-07 19:26:26","updated_at":"2014-08-07 19:26:26"}]

Time: 1.85 seconds, Memory: 18.50Mb

There was 1 error:

1) ExampleTest::testGetBlogPosts ErrorException: Trying to get property of non-object

/home/vagrant/Laravel/Homestead/Blog/app/tests/ExampleTest.php:22

FAILURES! Tests: 2, Assertions: 1, Errors: 1.

如果我在浏览器中访问这个端点，我会得到这个

[
{
id: 1,
user_id: 1,
title: "This is a test post",
subtitle: "",
post_body: "testststs",
created_at: "2014-08-07 19:26:04",
updated_at: "2014-08-07 19:26:04"
},
{
id: 2,
user_id: 18,
title: "Rem deserunt dolor odit tempore qui eaque labore.",
subtitle: "",
post_body: "Ea a adipisci molestiae vel dignissimos. Ea blanditiis et est.",
created_at: "2014-08-07 19:26:04",
updated_at: "2014-08-07 19:26:04"
}
]

Answer 1

希望你现在已经明白了，但这是我使用的:

$array = json_decode($response->getContent());