android - 我想在 volley 调用中将 json 对象作为参数发送

Question

您好，我知道使用 Map 发送参数的 voley 调用例如

private void SignInWithEmail() {
        //email= String.valueOf(mEmail.getText());
        //pass = String.valueOf(mPassword.getText());

        String url = RequestUrls.getInstance().signInByEmail();
        StringRequest mRequest = new StringRequest(Request.Method.POST, url, new Response.Listener<String>() {
            @Override
            public void onResponse(String response) {

                Log.v(TAG, "Login with email" + response);
                try {
                    JSONObject jsonResponse = new JSONObject(response);
                    String code = jsonResponse.getString("code");
                    if (code == "1") {

                        JSONArray UserDetailArray = jsonResponse.getJSONArray("document");
                        Log.v("Login with email", UserDetailArray.toString());
                        JSONObject finalObject = UserDetailArray.getJSONObject(0);
                        String User_email = finalObject.getString("Email");
                        getUserByEmail(User_email);
                    } else {
                        Toast.makeText(getApplicationContext(), "Invalid Email or Password", Toast.LENGTH_SHORT).show();
                        mPassword.setText("");
                    }
                } catch (JSONException e) {
                    e.printStackTrace();
                }
            }
        }, new Response.ErrorListener() {
            @Override
            public void onErrorResponse(VolleyError error) {
                Log.v(TAG, "Request for getUserByEmail Error: " + error.toString());
            }
        }) {
            @Override
            protected Map<String, String> getParams() throws AuthFailureError {

                Map<String, String> params = new HashMap<String, String>();
                params.put("Action", "GetUserByEmail");
                //Log.v("Login", "Action Email for put: " + email);
                params.put("UserName", email);
                params.put("Password", pass);
                return params;
            }
        };

        VolleySingleton.getInstance(getApplicationContext()).addToRequestQueue(mRequest);
    }

但我必须发送这个作为参数如何做到这一点

{
  "jsonrpc": "2.0",
  "method": "signUp",
  "id": "1",
  "params": {
    "email": "abc@gmail.com",
    "fname": "abc",
    "lname": "def",
    "pwd": "123"

  }
}

我是否必须添加标题或任何其他方法请建议我。我是 android 开发的新手。

这是 postman chrome 扩展的屏幕截图

请帮助我。

Answer 1

JsonObjectRequest jsObjRequest = new JsonObjectRequest
        (Request.Method.POST, url, json, new Response.Listener<JSONObject>() {

    @Override
    public void onResponse(JSONObject response) {

    }
}, new Response.ErrorListener() {

    @Override
    public void onErrorResponse(VolleyError error) {
        // TODO Auto-generated method stub

    }
});

您可以在 json 参数中使用上述代码发送您的 json。