c# - Android:在按钮上打开新布局单击并删除当前布局

Question

我目前正在尝试熟悉 Xamarin，因此我创建了一个小应用程序。在此应用程序中，我想单击一个打开新布局的按钮。但是当我在新布局中并按下手机上的后退按钮时，它会返回到以前的布局。我不想要那个。因为我要打开多个相同布局的实例，但我不想将这些实例保存在历史记录中。这是我的代码

public class AIVsPlayerActivity : Activity
{
    private int minValue = 0;
    private int maxValue = 100;
    private int valueToGuess;
    private int tries = 0;

    private bool hasWon = false;
    protected override void OnCreate(Bundle savedInstanceState)
    {
        base.OnCreate(savedInstanceState);

        // Set View
        SetContentView(Resource.Layout.AIVsPlayer);

        // Set value which has to be guessed
        var random = new Random();
        valueToGuess = random.Next(minValue, maxValue);

        // Create your application here

        TextView result = FindViewById<TextView>(Resource.Id.labResult);
        TextView labTries = FindViewById<TextView>(Resource.Id.labTries);
        Button button1 = FindViewById<Button>(Resource.Id.btnGuess);
        Button button2 = FindViewById<Button>(Resource.Id.btnNewRound);

        button1.Click += (sender, e) =>
        {
            var guess = FindViewById<EditText>(Resource.Id.tbGuess);
            int numberGuessed = int.Parse(guess.Text);

            if (numberGuessed > valueToGuess)
            {
                result.Text = "Your number is too high";
                tries++;
            }
            else if (numberGuessed < valueToGuess)
            {
                result.Text = "Your number is too low";
                tries++;
            }
            else if (numberGuessed == valueToGuess)
            {
                result.Text = "You made it! You've guessed my number!";
                //Console.WriteLine("{0} tries were needed", tries);
                hasWon = true;
            }
            labTries.Text = tries.ToString();

            if (hasWon)
            {
                button2.Visibility = ViewStates.Visible;
                button1.Visibility = ViewStates.Invisible;
            }
        };

        button2.Click += (sender, e) =>
        {
            var intent = new Intent(this, typeof(AIVsPlayerActivity));
            StartActivity(intent);
        };

    }
}

如果 button2 上的点击事件被触发，我想打开相同的布局，只是用一个新的随机数再次清空。我希望我能解释我的问题。

提前致谢

B.南瓜

Answer 1

打开新的 Activity 后，您必须调用 Finish:

button2.Click += (sender, e) =>
{
    var intent = new Intent(this, typeof(AIVsPlayerActivity));
    StartActivity(intent);
    Finish();
};