android - Spring for Android - 自定义休息模板

Question

我正在为 Android 使用 Spring 并通过以下方式提取 JSON 数据:

CourseActivity.java

private void getCourses()
{
  RestTemplate restTemplate = new RestTemplate();
  restTemplate.getMessageConverters().add(new MappingJacksonHttpMessageConverter());
  String url = "http://192.168.1.74:3000/andy/courses.json";
  Course[] coursesArray = restTemplate.getForObject(url, Course[].class);

  ...
}

Course.java

@JsonIgnoreProperties(ignoreUnknown = true)
public class Course implements Parcelable, DBObject
{
    @JsonProperty
    private String number = null;
    @JsonProperty
    private String title = null;
    @JsonProperty
    private int school_id = -1;
    @JsonProperty
    private String department = null;

    ...
}

JSON 调用返回这种类型的数据:

[{"id":1,"number":"CE-490","title":"Senior Design","school_id":1,"department":"Computer Engineering"},{"id":2,"number":"CE-491","title":"Introduction to Mobile App Development","school_id":1,"department":"Computer Engineering"}]

现在您可以看到 JSON 数据键直接映射到我的类(class)属性名称。

如果我想有不同的名字怎么办？具体来说，如果我的 JSON 返回一个键，例如“notify_on_follow”，我如何使用 Spring for Android 将其映射到不带下划线的“notifyOnFollow”？或者也许将“active”更改为“isActive”？

Answer 1

我找不到文档，但我很确定这会起作用:

@JsonProperty("notify_on_follow")
private SomeType notifyOnFollow;