android - GSON 返回异常 json 语法异常需要一个字符串，但在第 1 行第 15 列是 begin_object

Question

下面是我的代码。当我运行时它显示“json 语法异常需要一个字符串但是是 begin_object”。我不知道为什么会显示错误。

 {
"products": [
    {
        "name": "gam",
        "pplsft": "75665",
        "imei": "Ptwm ",
        "created_at": "2012-12-03 04:58:01"
    },
    {
        "name": "",
        "pplsft": "0",
        "imei": "",
        "created_at": "2012-12-03 05:44:01"
    },
    {
        "name": "gptw",
        "pplsft": "0",
        "imei": "at",
        "created_at": "2012-12-03 05:58:18"
    },
    {
        "name": "",
        "pplsft": "0",
        "imei": "",
        "created_at": "2012-12-03 23:32:06"
    },
    {
        "name": "",
        "pplsft": "0",
        "imei": "",
        "created_at": "2012-12-03 23:35:25"
    }
]
}

和类文件是，但我不知道如何使用 gson 创建用于 json 解析的类文件。谁能解释一下？？

  public class Results  {
public String name;
@SerializedName("pplsft")
public int pplsft;
@SerializedName("imei")
public String imei;
@SerializedName("created_at")
public int created_at;
     }

   public class SearchResponse  {

@SerializedName("products")
public List<Result> products;
@SerializedName("name")
public String name;
@SerializedName("pplsft")
public int pplsft;
@SerializedName("imei")
public String imei;
@SerializedName("created_at")
public int created_at;
public List<Result> getProducts() {
    return products;
}
public void setProducts(List<Result> products) {
    this.products = products;
}
public String getName() {
    return name;
}
public void setName(String name) {
    this.name = name;
}
public int getPplsft() {
    return pplsft;
}
public void setPplsft(int pplsft) {
    this.pplsft = pplsft;
}
public String getImei() {
    return imei;
}
public void setImei(String imei) {
    this.imei = imei;
}
public int getCreated_at() {
    return created_at;
}
public void setCreated_at(int created_at) {
    this.created_at = created_at;
}

   }

这是从json中调用数据的主要方法。

    response = gson.fromJson(reader, SearchResponse.class);
Toast.makeText(this,response.name, Toast.LENGTH_SHORT).show();
List<Result> list = response.products;

Answer 1

对于 JSON，您的对象应该如下所示:

SearchResponse response = gson.fromJson(reader, SearchResponse.class);

然后获取您的列表:

List<Product> mProducts = response.products;

要遍历列表，您需要执行以下操作:

for( Product pro : mProducts ){
    String pName = pro.name;
    ......
}

或者您可以手动完成(从第一个对象获取名称；

mProducts.get(0).name;

现在你的类(class):

public class SearchResponse  {

    @SerializedName("products")
    public List<Product> products;

    public class Product {

        @SerializedName("name")     
        public String name;

        @SerializedName("pplsft")
        public String pplsft;

        @SerializedName("imei")
        public String imei;

        @SerializedName("created_at")
        public String created_at;

    }
}

你的 JSON

{
   "products":[
      {
         "name":"gam",
         "pplsft":"75665",
         "imei":"Ptwm ",
         "created_at":"2012-12-03 04:58:01"
      },
      {
         "name":"",
         "pplsft":"0",
         "imei":"",
         "created_at":"2012-12-03 05:44:01"
      },
      {
         "name":"gptw",
         "pplsft":"0",
         "imei":"at",
         "created_at":"2012-12-03 05:58:18"
      },
      {
         "name":"",
         "pplsft":"0",
         "imei":"",
         "created_at":"2012-12-03 23:32:06"
      },
      {
         "name":"",
         "pplsft":"0",
         "imei":"",
         "created_at":"2012-12-03 23:35:25"
      }
   ]
}

Perhaps the Solution to this Post也可能对您有所帮助。