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android - 将 Android 应用程序与 SQLite 数据库连接时找不到表名

转载 作者:搜寻专家 更新时间:2023-11-01 08:51:29 25 4
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我是 android 编程的新手,所以请帮助我。我已经使用 SQLite 浏览器创建了数据库,我尝试将我的应用程序与该数据库文件连接,但它不起作用,错误日志显示“没有这样的表:datasaya”。在我创建的数据库中只有 1 个表时,怎么会发生这种情况。

这是我的 sqlite 帮助程序类:

public class SQLiteHelper extends SQLiteOpenHelper {


private static String DB_PATH="/data/data/com.example.latihandbsqlite/databases/";
private static String DB_NAME = "cekdatabase.sqlite";
private static int VERSION =1;
private SQLiteDatabase myDataBase;
private final Context myContext;


public SQLiteHelper(Context context) {

super(context, DB_NAME, null, VERSION);
myContext = context;

try {

createDatabase();
} catch (IOException ioe) {

throw new Error("Unable to create database");
}
}

public void createDatabase() throws IOException {

boolean dbExist = checkDataBase();

if (dbExist) {
System.out.println("DB EXIST");
} else {
this.getReadableDatabase();
this.close();
copyDataBase();
}
}


private void copyDataBase() throws IOException {

InputStream myInput = myContext.getAssets().open(DB_NAME);

String outFileName = DB_PATH + DB_NAME;
OutputStream myOutput = new FileOutputStream(outFileName);

byte[] buffer = new byte[1024];
int length;
while ((length = myInput.read(buffer)) > 0) {

myOutput.write(buffer, 0, length);
}

myOutput.flush();
myOutput.close();
myInput.close();
}

private boolean checkDataBase() {

SQLiteDatabase checkDB = null;

try {

String myPath = DB_PATH + DB_NAME;
checkDB = SQLiteDatabase.openDatabase(myPath,
null, SQLiteDatabase.OPEN_READONLY);
} catch (SQLiteException e) {

System.out.println("Database does't exist yet.");
}

if (checkDB != null) {

checkDB.close(); }

return checkDB != null ? true : false;
}

@Override

public synchronized void close() {

if (myDataBase != null) myDataBase.close();

super.close();

} @Override

public void onCreate(SQLiteDatabase arg0) {


} @Override

public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) {


}

}

这是我的 SQLiteConnector 类:

     public class SQLiteConnector {

private SQLiteDatabase database;
private SQLiteHelper sqlHelper;
private Cursor cursor;

private static final String TABLE_RECORD = "datasaya";

public SQLiteConnector(Context context) {

sqlHelper = new SQLiteHelper(context);

} // Getting All records


public List<String> getAllRecord() {

List<String> namagambar = new ArrayList<String>();
String selectQuery = "SELECT * FROM " + TABLE_RECORD;

database = sqlHelper.getReadableDatabase();
cursor = database.rawQuery(selectQuery, null);

if (cursor.moveToFirst()) {

do {

namagambar.add(cursor.getString(1));
} while (cursor.moveToNext());

}
database.close();
return namagambar;

}

}

我该如何解决这个问题?

最佳答案

删除数据库名称的点。从: cekdatabase.sqlite 到: cekdatabase

关于android - 将 Android 应用程序与 SQLite 数据库连接时找不到表名,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/22961948/

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