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Android ListView 添加了太多项目

转载 作者:搜寻专家 更新时间:2023-11-01 08:43:42 25 4
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我目前正在使用 for 循环在 ListView 元素内的 LinearLayout 内添加 TextView,因为我必须在其中添加的 TextView 的数量是可变的。我像往常一样将项目添加到 ListViews。问题是,当我滚动时,项目开始变得越来越多,而当我向上滚动时,我最终得到数百个项目。我认为这是因为 ListView 正在重新加载并再次循环通过 for 循环,因此多次添加每个 TextView。我能阻止吗?

我的代码:

public class ListViewAdapter extends ArrayAdapter<RowItem> {

private final Context context;

public ListViewAdapter(Context context, List<RowItem> items) {
super(context, R.layout.list, items);
this.context = context;
}

private class ViewHolder {
TextView title;
LinearLayout linearLayout;
}

public View getView(int position, View convertView, ViewGroup parent) {
ViewHolder holder;
RowItem rowItem = getItem(position);

LayoutInflater mInflater = (LayoutInflater) context.getSystemService(Activity.LAYOUT_INFLATER_SERVICE);

if (convertView == null) {
convertView = mInflater.inflate(R.layout.list_list, null);
holder = new ViewHolder();
holder.title = (TextView) convertView.findViewById(R.id.list_line);
holder.linearLayout = (LinearLayout) convertView.findViewById(R.id.list_linear);
convertView.setTag(holder);
} else {
holder = (ViewHolder) convertView.getTag();
}

holder.title.setText(rowItem.getTitle());

String data = rowItem.getData();
String[] split0 = data.split("=");

Log.e("DATA", data);
Log.e("LINE", rowItem.getTitle());

for (int j = 0; j < split0.length; j++) {
String[] split1 = split0[j].split(":");

LinearLayout parentLayout = new LinearLayout(MainActivity.context);
parentLayout.setLayoutParams(new LinearLayout.LayoutParams(LinearLayout.LayoutParams.MATCH_PARENT, LinearLayout.LayoutParams.WRAP_CONTENT));
parentLayout.setOrientation(LinearLayout.HORIZONTAL);

for (int k = 0; k < split1.length; k++) {
TextView textView = new TextView(MainActivity.context);
textView.setText(split1[k]);
textView.setLayoutParams(new LinearLayout.LayoutParams(LinearLayout.LayoutParams.MATCH_PARENT, LinearLayout.LayoutParams.WRAP_CONTENT, 1.0f));
textView.setGravity(Gravity.CENTER_HORIZONTAL | Gravity.CENTER_VERTICAL);
textView.setTextSize(18);

parentLayout.addView(textView);
}
holder.linearLayout.addView(parentLayout);
}

return convertView;
}
}

对于一个条目,我的数据方案看起来像这样:

text1:text2=text3:text4

它在列表中的样子:

text1    text2
text3 text4

最佳答案

问题是 ArrayAdapter 会在每次行变为可见时调用 getView()。如果该行之前设置过,则会在convertView参数中传入之前设置的View。

参见 here了解详情。来自 the documentation对于 convertView:

The old view to reuse, if possible. Note: You should check that this view is non-null and of an appropriate type before using. If it is not possible to convert this view to display the correct data, this method can create a new view. Heterogeneous lists can specify their number of view types, so that this View is always of the right type (see getViewTypeCount() and getItemViewType(int)).

编辑:由于最初提出的代码引起了问题,看起来您可能终究无法使用标准 View 持有者设计模式。您有一个独特的设置,您在每行中创建动态数量的项目。

你可以做一些稍微优化的事情,你不必在每个 getView() 调用时调用 inflate(),但仍然重新- 每次调用 getView() 时创建 ViewHolder,以便在滚动时填充正确的数据:

public View getView(int position, View convertView, ViewGroup parent) {
ViewHolder holder;
RowItem rowItem = getItem(position);

LayoutInflater mInflater = (LayoutInflater) context.getSystemService(Activity.LAYOUT_INFLATER_SERVICE);

if (convertView == null) {
convertView = mInflater.inflate(R.layout.list_list, null);

}

holder = new ViewHolder();
holder.title = (TextView) convertView.findViewById(R.id.list_line);
holder.linearLayout = (LinearLayout) convertView.findViewById(R.id.list_linear);
convertView.setTag(holder);


holder.title.setText(rowItem.getTitle());

String data = rowItem.getData();
String[] split0 = data.split("=");

Log.e("DATA", data);
Log.e("LINE", rowItem.getTitle());

for (int j = 0; j < split0.length; j++) {
String[] split1 = split0[j].split(":");

LinearLayout parentLayout = new LinearLayout(MainActivity.context);
parentLayout.setLayoutParams(new LinearLayout.LayoutParams(LinearLayout.LayoutParams.MATCH_PARENT, LinearLayout.LayoutParams.WRAP_CONTENT));
parentLayout.setOrientation(LinearLayout.HORIZONTAL);

for (int k = 0; k < split1.length; k++) {
TextView textView = new TextView(MainActivity.context);
textView.setText(split1[k]);
textView.setLayoutParams(new LinearLayout.LayoutParams(LinearLayout.LayoutParams.MATCH_PARENT, LinearLayout.LayoutParams.WRAP_CONTENT, 1.0f));
textView.setGravity(Gravity.CENTER_HORIZONTAL | Gravity.CENTER_VERTICAL);
textView.setTextSize(18);

parentLayout.addView(textView);
}
holder.linearLayout.addView(parentLayout);
}


return convertView;
}

如果这不起作用,您可以回到基础,在每次调用 getView() 时完全重新创建 View :

public View getView(int position, View convertView, ViewGroup parent) {
ViewHolder holder;
RowItem rowItem = getItem(position);

LayoutInflater mInflater = (LayoutInflater) context.getSystemService(Activity.LAYOUT_INFLATER_SERVICE);

//if (convertView == null) {
convertView = mInflater.inflate(R.layout.list_list, null);
holder = new ViewHolder();
holder.title = (TextView) convertView.findViewById(R.id.list_line);
holder.linearLayout = (LinearLayout) convertView.findViewById(R.id.list_linear);
convertView.setTag(holder);

holder.title.setText(rowItem.getTitle());

String data = rowItem.getData();
String[] split0 = data.split("=");

Log.e("DATA", data);
Log.e("LINE", rowItem.getTitle());

for (int j = 0; j < split0.length; j++) {
String[] split1 = split0[j].split(":");

LinearLayout parentLayout = new LinearLayout(MainActivity.context);
parentLayout.setLayoutParams(new LinearLayout.LayoutParams(LinearLayout.LayoutParams.MATCH_PARENT, LinearLayout.LayoutParams.WRAP_CONTENT));
parentLayout.setOrientation(LinearLayout.HORIZONTAL);

for (int k = 0; k < split1.length; k++) {
TextView textView = new TextView(MainActivity.context);
textView.setText(split1[k]);
textView.setLayoutParams(new LinearLayout.LayoutParams(LinearLayout.LayoutParams.MATCH_PARENT, LinearLayout.LayoutParams.WRAP_CONTENT, 1.0f));
textView.setGravity(Gravity.CENTER_HORIZONTAL | Gravity.CENTER_VERTICAL);
textView.setTextSize(18);

parentLayout.addView(textView);
}
holder.linearLayout.addView(parentLayout);
}

//}

return convertView;
}

关于Android ListView 添加了太多项目,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/30402985/

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