gpt4 book ai didi

java - 更改 ListView 的 ArrayList 是对静态的适当使用吗?

转载 作者:搜寻专家 更新时间:2023-11-01 08:36:54 24 4
gpt4 key购买 nike

我正在制作两个 Activity ,一个带有自定义任务 ListView 的主页,您可以在该主页上单击“+”并添加一个新任务。它会将您重定向到 addTask Activity ,这是一个带有调用 submit_task_to_list 按钮的表单。

主要 Activity

static KittyAdapter mAdapter; // Could be listview adapter
static ArrayList<Tasks> tasks = new ArrayList<Tasks>();

AddTaskActivity,当一个按钮被点击时

public void submit_task_to_list(View v) {
EditText title = (EditText) findViewById(R.id.Title);
EditText desc = (EditText) findViewById(R.id.Description);
Tasks newTask = new Tasks(title.toString(), desc.toString());
TaskCentral.tasks.add(newTask);
TaskCentral.mAdapter.notifyDataSetChanged();
}

有没有比使用 static 关键字更好的解决方案?我以前过度使用静态,随着我的其他应用程序变得越来越复杂,处理起来很痛苦。我想尽量减少使用此应用的坏习惯。

我试图将 onClickListener 移动到 mainactivity 但 android 找不到它。

完整代码:主要 Activity

public class TaskCentral extends Activity {

static KittyAdapter mAdapter; // Could be listview adapter
static ArrayList<Tasks> tasks = new ArrayList<Tasks>();

@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_task_central);

String[] tString = {"Hi", "My", "name", "is", "Kitty"};
Tasks T1 = new Tasks("m", "p");
Tasks T2 = new Tasks("m", "p");
Tasks T3 = new Tasks("m", "p");
Tasks T4 = new Tasks("m", "p");
tasks.add(T1);
tasks.add(T2);
tasks.add(T3);
Tasks[] TaskArr = new Tasks[tasks.size()];
TaskArr = tasks.toArray(TaskArr);

ListView taskCentral = (ListView)findViewById(R.id.Central);
mAdapter = new KittyAdapter(this, TaskArr);
taskCentral.setAdapter(mAdapter);
// mAdapter.notifyDataSetChanged();
}

@Override
public boolean onCreateOptionsMenu(Menu menu) {
// Inflate the menu; this adds items to the action bar if it is present.
getMenuInflater().inflate(R.menu.menu_task_central, menu);
return true;
}

@Override
public boolean onOptionsItemSelected(MenuItem item) {
// Handle action bar item clicks here. The action bar will
// automatically handle clicks on the Home/Up button, so long
// as you specify a parent activity in AndroidManifest.xml.
int id = item.getItemId();

//noinspection SimplifiableIfStatement
if (id == R.id.action_settings) {
return true;
}

return super.onOptionsItemSelected(item);
}
public void addNew(View v) {
Intent addTaskIntent = new Intent(this, AddTaskActivity.class);
startActivity(addTaskIntent);
}

我的适配器

公共(public)类 KittyAdapter 扩展 ArrayAdapter {

public KittyAdapter(Context context, Tasks[] items) {
super(context, R.layout.custom_task_layout, items);
}

@Override
public View getView(int position, View convertView, ViewGroup parent) {
LayoutInflater myinf = LayoutInflater.from(getContext());
View customView = myinf.inflate(R.layout.custom_task_layout, parent, false);

Tasks singleTask = getItem(position);
CheckBox done = (CheckBox) customView.findViewById(R.id.Done);
TextView myItemText = (TextView) customView.findViewById(R.id.ItemText);

myItemText.setText(singleTask.getTitle());

return customView;
}

如何从第二个 Activity 添加项目并通知数据集已更改?

最佳答案

这是我会做的:

在任务中心:

final static int REQUEST_CODE_ADD_TASK = 324234;

@Override
protected void onActivityResult(final int requestCode, final int resultCode, final Intent data) {
if (resultCode == Activity.RESULT_OK) {
switch (requestCode) {
case REQUEST_CODE_ADD_TASK:
String title = data.getStringExtra("title");
String desc = data.getStringExtra("desc");
Tasks newTask = new Tasks(title, desc);
tasks.add(newTask);
mAdapter.notifyDataSetChanged();
}
}
}

并像这样启动 AddTaskActivity:

public void addNew(View v) {
Intent addTaskIntent = new Intent(this, AddTaskActivity.class);
startActivityForResult(addTaskIntent, REQUEST_CODE_ADD_TASK);
}

并在 AddTaskActivity 中完成(onClickListener?):

Intent intent=new Intent();
intent.putExtra("title", title.toString());
intent.putExtra("desc", desc.toString());
setResult(RESULT_OK, intent);
finish();

关于java - 更改 ListView 的 ArrayList 是对静态的适当使用吗?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/35963829/

24 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com