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android - 如何将 Android 应用程序连接到 python-socketio 后端?

转载 作者:搜寻专家 更新时间:2023-11-01 08:32:30 35 4
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我目前正在运行一个完美连接到我的 JavaScript 客户端的 Python SocketIO 服务器。我正在使用 socketio android example chat app编写 Android 代码时,它与 NodeJS 服务器完美配合,但当我改用 Python 服务器时,它无法连接。

如何从 Android 连接到 Ptyhon-SocketIO 服务器?

安卓代码:

public class HomeActivity extends AppCompatActivity
implements NavigationView.OnNavigationItemSelectedListener {

private final String TAG = "MainActivity";

Button btnCore0, btnCore1, btnCPUUsage;
private ProgressBar progressBar;

private Socket mSocket;

{
try {
mSocket = IO.socket(Constants.SERVER_URL);
} catch (URISyntaxException e) {
Log.e(TAG, e.getMessage());
}
}

@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_home);
Toolbar toolbar = (Toolbar) findViewById(R.id.toolbar);
setSupportActionBar(toolbar);

FloatingActionButton fab = (FloatingActionButton) findViewById(R.id.fab);
fab.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View view) {
Snackbar.make(view, "Replace with your own action", Snackbar.LENGTH_LONG)
.setAction("Action", null).show();
}
});

DrawerLayout drawer = (DrawerLayout) findViewById(R.id.drawer_layout);
ActionBarDrawerToggle toggle = new ActionBarDrawerToggle(
this, drawer, toolbar, R.string.navigation_drawer_open, R.string.navigation_drawer_close);
drawer.setDrawerListener(toggle);
toggle.syncState();

NavigationView navigationView = (NavigationView) findViewById(R.id.nav_view);
navigationView.setNavigationItemSelectedListener(this);

btnCore0 = (Button) findViewById(R.id.btnCore0);
btnCore1 = (Button) findViewById(R.id.btnCore1);
btnCPUUsage = (Button) findViewById(R.id.btnCPUUsage);
progressBar = (ProgressBar) findViewById(R.id.progressBar);

// Make buttons invisible
btnCore0.setVisibility(View.INVISIBLE);
btnCore1.setVisibility(View.INVISIBLE);
btnCPUUsage.setVisibility(View.INVISIBLE);
// Make progress bar visible
progressBar.setVisibility(View.VISIBLE);

mSocket.on("status-update", onNewMessage);
mSocket.on(Socket.EVENT_DISCONNECT, onSocketDisconnected);
mSocket.connect();
}

private Emitter.Listener onNewMessage = new Emitter.Listener() {
@Override
public void call(final Object... args) {
HomeActivity.this.runOnUiThread(new Runnable() {
@Override
public void run() {
Log.d(TAG, "New message 090909***");
JSONObject data = (JSONObject) args[0];
int core0 = 0;
int core1 = 0;
int cpu_usage_in = 0;
try {
core0 = data.getInt("core0_in");
core1 = data.getInt("core1_in");
cpu_usage_in = data.getInt("cpu_usage_in");
} catch (JSONException e) {
Log.e(TAG, e.getMessage());
}

btnCore0.setText(getResources().getString(R.string.core0, String.valueOf(core0)));
btnCore1.setText(getResources().getString(R.string.core1, String.valueOf(core1)));
btnCPUUsage.setText(getResources().getString(R.string.cpu_usge, String.valueOf(cpu_usage_in)));

updateButtonBackgroundColor(btnCore0, core0);
updateButtonBackgroundColor(btnCore1, core1);
updateButtonBackgroundColor(btnCPUUsage, cpu_usage_in);

onServerDataReceived();
}
});
}
};

接下来是每秒发出一次的 Pyhton 服务器。这个,我知道工作正常,因为我可以从 JavaScript 应用程序连接到它。Python代码:

from flask import Flask, render_template
from flask_socketio import SocketIO
from gcm import GCM

eventlet.monkey_patch()
app = Flask(__name__)
socket = SocketIO(app, logger=True, engineio_logger=True)

class Server(threading.Thread):
def __init__(self, thread_id):
threading.Thread.__init__(self)
self.threadID = thread_id

def run(self):
print("Starting " + self.name)
serve()
print("Exiting " + self.name)


def serve():
if __name__ == '__main__':
eventlet.wsgi.server(eventlet.wrap_ssl(eventlet.listen(('', 8000)), certfile='/home/garthtee/cert.pem', keyfile='/home/garthtee/privkey.pem'), app)

server_thread = Server("Server-thread")
server_thread.start()
threads.append(server_thread)
print("Started @ " + str(get_time()))
while True:
sensors.init()
try:
for chip in sensors.iter_detected_chips():
# print('%s at %s' % (chip, chip.adapter_name))
for feature in chip:
if feature.label == 'Core 0':
core0 = feature.get_value()
elif feature.label == 'Core 1':
core1 = feature.get_value()
for x in range(1):
cpu_usage = str(psutil.cpu_percent(interval=1))
finally:
socket.emit('status-update', {'core0_in': core0, 'core1_in': core1, 'cpu_usage_in': cpu_usage, 'users': users})

alert_checker(avg_temp, users)
sensors.cleanup()
time.sleep(1)

出现以下错误:

SSLError: [SSL: SSL_HANDSHAKE_FAILURE] ssl 握手失败 (_ssl.c:1754)

最佳答案

我从 Github 下载了 SocketIO python 库

我修改了示例代码如下:

import socketio
import eventlet
import eventlet.wsgi
from flask import Flask, render_template

sio = socketio.Server()
app = Flask(__name__)

@app.route('/')
def index():
"""Serve the client-side application."""
return render_template('index.html')

@sio.on('connect', namespace='/')
def connect(sid, environ):
print("connect ", sid)

@sio.on('add user', namespace='/')
def login(sid, environ):
print("login ", sid)
sio.emit('login', room=sid)

@sio.on('new message', namespace='/')
def message(sid, data):
print("message ", data)
sio.emit('reply', room=sid)

@sio.on('disconnect', namespace='/')
def disconnect(sid):
print('disconnect ', sid)

if __name__ == '__main__':
# wrap Flask application with engineio's middleware
app = socketio.Middleware(sio, app)

# deploy as an eventlet WSGI server
eventlet.wsgi.server(eventlet.listen(('', 8000)), app)

然后我克隆了 Android example chat项目,以及我在 Constants.java 中唯一更改的内容:

public static final String CHAT_SERVER_URL = "http://MY_LOCAL_IP:8000";

Android 应用程序可以连接。我在应用程序中看到它,也在 python 控制台中看到它。如果你删除一些不必要的解析部分(应用程序崩溃,因为响应不同),你也可以在 python 中看到你的消息。

您是否尝试过先在没有 SSL 的情况下运行您的服务器应用程序?

也许这就是问题所在。在 Android 上,您可以使用 IO.setDefaultSSLContext(SSLContext sslContext) 来设置 SSL。

关于android - 如何将 Android 应用程序连接到 python-socketio 后端?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/39489919/

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