android - 无法从谷歌个人资料图片网址获取位图

Question

我有一个应用程序，我试图从通过谷歌集成获得的链接中检索图像。但是，每当我尝试将图片转换为位图时，它总是给我一个错误。代码和错误如下:

代码:

if (google_user_gallery_pic.isEmpty() == true)
{
    if (google_user_pic.isEmpty() == false)
    {
        onPost = null;
        onPost2 = null;
        onPost = getBitmapFromURL(google_user_pic);
        onPost2 = onPost2.createScaledBitmap(onPost, 100, 100, false);
    }

    else
    {
        onPost = null;
        onPost2 = null;
        onPost = BitmapFactory.decodeFile(google_user_gallery_pic);
        if (onPost == null)
        {
            onPost2 = BitmapFactory.decodeResource(getResources(), R.drawable.the_smallperson);
        }

        else
        {
            onPost2 = onPost2.createScaledBitmap(onPost, 100, 100, false);
        }
    }
}

else
{
    onPost = null;
    onPost2 = null;
    onPost = BitmapFactory.decodeFile(google_user_gallery_pic);
    if (onPost == null)
    {
        onPost2 = BitmapFactory.decodeResource(getResources(), R.drawable.the_smallperson);
        //onPost2 = onPost2.createScaledBitmap(onPost, 100, 100, false);
    }

    else
    {
        onPost2 = onPost2.createScaledBitmap(onPost, 100, 100, false);
    }
}

错误:

E/BitmapFactory: Unable to decode stream: java.io.FileNotFoundException: https:/lh3.googleusercontent.com/-HW5Tk9h1V2I/AAAAAAAAAAI/AAAAAAAADA8/7UbMeHbyFLM/photo.jpg: open failed: ENOENT (No such file or directory)

网址:

https://lh3.googleusercontent.com/-HW5Tk9h1V2I/AAAAAAAAAAI/AAAAAAAADA8/7UbMeHbyFLM/photo.jpg

此 url 在一个页面上有效，但在另一个页面上无效。这两个页面都是 fragment Activity 。任何帮助将不胜感激，谢谢!

Answer 1

尝试将 if 和 else 条件反转为如下所示:

if (google_user_gallery_pic.isEmpty() == false)
{
    if (google_user_pic.isEmpty() == false)
    {
        onPost = null;
        onPost2 = null;
        onPost = getBitmapFromURL(google_user_pic);
        onPost2 = onPost2.createScaledBitmap(onPost, 100, 100, false);
    }

    else
    {
        onPost = null;
        onPost2 = null;
        onPost = BitmapFactory.decodeFile(google_user_gallery_pic);
        if (onPost == null)
        {
            onPost2 = BitmapFactory.decodeResource(getResources(), R.drawable.the_smallperson);
        }

        else
        {
            onPost2 = onPost2.createScaledBitmap(onPost, 100, 100, false);
        }
    }
}

else
{
    onPost = null;
    onPost2 = null;
    onPost = BitmapFactory.decodeFile(google_user_gallery_pic);
    if (onPost == null)
    {
        onPost2 = BitmapFactory.decodeResource(getResources(), R.drawable.the_smallperson);
        //onPost2 = onPost2.createScaledBitmap(onPost, 100, 100, false);
    }

    else
    {
        onPost2 = onPost2.createScaledBitmap(onPost, 100, 100, false);
    }
}

因为给定了权限和其他任何东西而不是这个代码 fragment ，所以除此之外没有任何问题