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Android,将字符串从应用程序发送到网络服务器

转载 作者:搜寻专家 更新时间:2023-11-01 07:57:12 25 4
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我正在尝试制作一个应用程序,我应该将数据从应用程序发送到网络服务器。到目前为止,我一直在搜索,但未能找到一个有效的示例,我发现一些使用 asynctask 的方法不起作用,因此非常感谢您的帮助!

最佳答案

试试下面的代码:-

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import org.apache.http.HttpResponse;
import org.apache.http.client.HttpClient;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.entity.StringEntity;
import org.apache.http.impl.client.DefaultHttpClient;
import org.json.JSONObject;
import android.net.ConnectivityManager;
import android.net.NetworkInfo;
import android.os.AsyncTask;
import android.os.Bundle;
import android.util.Log;
import android.view.View;
import android.view.View.OnClickListener;
import android.widget.Button;
import android.widget.EditText;
import android.widget.TextView;
import android.widget.Toast;
import android.app.Activity;
import com.hmkcode.android.vo.Person;

public class MainActivity extends Activity implements OnClickListener {

TextView tvIsConnected;
EditText etName,etCountry,etTwitter;
Button btnPost;

Person person;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);

// get reference to the views
tvIsConnected = (TextView) findViewById(R.id.tvIsConnected);
etName = (EditText) findViewById(R.id.etName);
etCountry = (EditText) findViewById(R.id.etCountry);
etTwitter = (EditText) findViewById(R.id.etTwitter);
btnPost = (Button) findViewById(R.id.btnPost);

// check if you are connected or not
if(isConnected()){
tvIsConnected.setBackgroundColor(0xFF00CC00);
tvIsConnected.setText("You are conncted");
}
else{
tvIsConnected.setText("You are NOT conncted");
}

// add click listener to Button "POST"
btnPost.setOnClickListener(this);

}

public static String POST(String url, Person person){
InputStream inputStream = null;
String result = "";
try {

// 1. create HttpClient
HttpClient httpclient = new DefaultHttpClient();

// 2. make POST request to the given URL
HttpPost httpPost = new HttpPost(url);

String json = "";

// 3. build jsonObject
JSONObject jsonObject = new JSONObject();
jsonObject.accumulate("name", person.getName());
jsonObject.accumulate("country", person.getCountry());
jsonObject.accumulate("twitter", person.getTwitter());

// 4. convert JSONObject to JSON to String
json = jsonObject.toString();

// ** Alternative way to convert Person object to JSON string usin Jackson Lib
// ObjectMapper mapper = new ObjectMapper();
// json = mapper.writeValueAsString(person);

// 5. set json to StringEntity
StringEntity se = new StringEntity(json);

// 6. set httpPost Entity
httpPost.setEntity(se);

// 7. Set some headers to inform server about the type of the content
httpPost.setHeader("Accept", "application/json");
httpPost.setHeader("Content-type", "application/json");

// 8. Execute POST request to the given URL
HttpResponse httpResponse = httpclient.execute(httpPost);

// 9. receive response as inputStream
inputStream = httpResponse.getEntity().getContent();

// 10. convert inputstream to string
if(inputStream != null)
result = convertInputStreamToString(inputStream);
else
result = "Did not work!";

} catch (Exception e) {
Log.d("InputStream", e.getLocalizedMessage());
}

// 11. return result
return result;
}

public boolean isConnected(){
ConnectivityManager connMgr = (ConnectivityManager) getSystemService(Activity.CONNECTIVITY_SERVICE);
NetworkInfo networkInfo = connMgr.getActiveNetworkInfo();
if (networkInfo != null && networkInfo.isConnected())
return true;
else
return false;
}
@Override
public void onClick(View view) {

switch(view.getId()){
case R.id.btnPost:
if(!validate())
Toast.makeText(getBaseContext(), "Enter some data!", Toast.LENGTH_LONG).show();
// call AsynTask to perform network operation on separate thread
new HttpAsyncTask().execute("http://hmkcode.appspot.com/jsonservlet");
break;
}

}
private class HttpAsyncTask extends AsyncTask<String, Void, String> {
@Override
protected String doInBackground(String... urls) {

person = new Person();
person.setName(etName.getText().toString());
person.setCountry(etCountry.getText().toString());
person.setTwitter(etTwitter.getText().toString());

return POST(urls[0],person);
}
// onPostExecute displays the results of the AsyncTask.
@Override
protected void onPostExecute(String result) {
Toast.makeText(getBaseContext(), "Data Sent!", Toast.LENGTH_LONG).show();
}
}

private boolean validate(){
if(etName.getText().toString().trim().equals(""))
return false;
else if(etCountry.getText().toString().trim().equals(""))
return false;
else if(etTwitter.getText().toString().trim().equals(""))
return false;
else
return true;
}
private static String convertInputStreamToString(InputStream inputStream) throws IOException{
BufferedReader bufferedReader = new BufferedReader( new InputStreamReader(inputStream));
String line = "";
String result = "";
while((line = bufferedReader.readLine()) != null)
result += line;

inputStream.close();
return result;

}
}

查看以下链接了解更多信息:-

http://hmkcode.com/android-send-json-data-to-server/

http://androidexample.com/How_To_Make_HTTP_POST_Request_To_Server_-_Android_Example/index.php?view=article_discription&aid=64&aaid=89

关于Android,将字符串从应用程序发送到网络服务器,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/26629026/

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