android - 如何在asynctask中写入解析后的json

Question

我正在开发通过添加参数用户名和密码从 URL 解析数据并更新它的应用程序，解析已完成但我无法更新或写/回发到服务器。

private class abc extends AsyncTask<String,String,String>{

    String response = "";

    @Override
    protected String doInBackground(String... arg0) {
        // TODO Auto-generated method stub

        DefaultHttpClient client = new DefaultHttpClient();
        HttpPost p1 = new HttpPost("Url");

        List<NameValuePair>data = new ArrayList<NameValuePair>(2);               
            data.add(new BasicNameValuePair("UserName", "abc"));
            data.add(new BasicNameValuePair("Password", "def"));

            try {
                  p1.setEntity(new UrlEncodedFormEntity(data));
                  HttpResponse execute = client.execute(p1);
                  InputStream content = execute.getEntity().getContent();
                  BufferedReader buffer = new BufferedReader(new InputStreamReader(content));
                  String s = "";
                  while ((s = buffer.readLine()) != null) {
                    response += s;
                  }             

            } catch (UnsupportedEncodingException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            } catch (ClientProtocolException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            } catch (IOException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }  
        return response;
    }

@Override
protected void onPostExecute(String result) {
    // TODO Auto-generated method stub

    try {
        JSONObject inf = new JSONObject(result);
        int id = inf.getInt("UserID");
        String username = inf.getString("UserName");

        TextView t1 = (TextView)findViewById(R.id.textView1);
        t1.setText("user id :"+id+"\n"+"user name :"+UserName);

    } catch (JSONException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }       
    super.onPostExecute(result);
}   

Answer 1

在 doInBackground 中使用用户名和密码以及 userId 传递您的参数username 和 password 是您当前的用户名和密码(如获取 edittext 值)并使用 post 方法调用 asyntask