php - 带有参数错误代码 500 的 Android http post

Question

我想通过 http post 添加新的支持数据。我得到一个错误响应代码是 500。我检查了代码和 php 文件，我看不出有任何问题。而且我没有完成代码如何在解决 500 错误后得到结果。

NewSupport.java

try{
    URL url = new URL("myurl/db_newSupport.php");

    HttpURLConnection conn = (HttpURLConnection) url.openConnection();
    conn.setReadTimeout(15000);
    conn.setConnectTimeout(15000);
    conn.setRequestMethod("POST");
    conn.setDoInput(true);
    conn.setDoOutput(true);

    Uri.Builder builder = new Uri.Builder()
            .appendQueryParameter("uniq",  "UNIQ")
            .appendQueryParameter("data",  "DATA")
            .appendQueryParameter("date",  "DATE");
    String query = builder.build().getEncodedQuery();

    OutputStream os = conn.getOutputStream();
    BufferedWriter writer = new BufferedWriter(
            new OutputStreamWriter(os, "UTF-8"));
    writer.write(query);

    writer.flush();
    writer.close();
    os.close();

    int responseCode=conn.getResponseCode();
    if (responseCode == HttpURLConnection.HTTP_OK) {
        BufferedReader in=new BufferedReader(new InputStreamReader(conn.getInputStream()));
        StringBuffer sb = new StringBuffer("");
        String line="";

        while((line = in.readLine()) != null) {

            sb.append(line);
            break;
        }

        in.close();
    }
}
catch(Exception e){
    e.printStackTrace();
}

db_newSupport.php

$response = array();
if (isset($_POST['uniq']) && isset($_POST['data']) && isset($_POST['date'])) {

    $uniq  = $_POST['uniq'];
    $data  = $_POST['data'];
    $date  = $_POST['date'];

    require_once __DIR__ . '/db_connect.php';
    $db    = new DB_CONNECT();
    $result= mysql_query("INSERT INTO new(uniq, data, date) VALUES('$uniq', '$data', '$date')");

    if ($result) {
        $response["code"]  = 1;
        $response["info"]  = "successfully";

        echo json_encode($response);
    } else {
        $response["code"]  = 0;
        $response["info"]  = "error";

        echo json_encode($response);
    }
} else {
    $response["code"] = 99;
    $response["info"] = "error";

    echo json_encode($response);
}
?>

Answer 1

这是服务器端的问题。

1. 启用 PHP 错误:https://stackoverflow.com/a/845025/1979882

2. 将 POST 方法改为 GET 以检查结果是任何浏览器以简化调试。

3.在此处写入结果日志。

看这个:https://stackoverflow.com/a/9711595/1979882

还有这个:https://stackoverflow.com/a/9717056/1979882

简而言之，执行此 chmod -R 755/usr/local/apache/htdocs/