java - StartActivity 一旦用户在权限屏幕上单击允许

Question

我的一项 Activity 需要位置许可，我写了下面的代码来获得许可。但在这种情况下，如果应用最初没有位置权限，用户需要点击两次才能打开 Activity 。我能否进行一些更改，以便一旦用户在“权限”屏幕上单击“允许”，然后才会触发 intent。

 int PERMISSION_ALL = 1;
                            String[] PERMISSIONS = new String[0];
                            if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.KITKAT) {
                                PERMISSIONS = new String[]{
                                        Manifest.permission.ACCESS_FINE_LOCATION};
                            }

                            if (!hasPermissions(getApplicationContext(), PERMISSIONS)) {
                                ActivityCompat.requestPermissions(StartupActivity.this, PERMISSIONS, PERMISSION_ALL);
                            }

                            if (hasPermissions(getApplicationContext(), PERMISSIONS)) {
                                new Thread(new Runnable() {
                                    @Override
                                    public void run() {
                                        Intent intent = new Intent(StartActivity.this, Details.class);
                                        startActivity(intent);
                                    }
                                }).start();
                            }

Answer 1

override onRequestPermissionsResult 如果权限被授予，则从那里开始你的Activity

@Override
public void onRequestPermissionsResult(int requestCode, @NonNull String[] permissions, @NonNull int[] grantResults) {
    if(requestCode == PERMISSION_ALL){
        if(grantResults.length>0 && grantResults[0]==PackageManager.PERMISSION_GRANTED ){

             new Thread(new Runnable() {
                    @Override
                    public void run() {
                        Intent intent = new Intent(StartActivity.this, Details.class);
                        startActivity(intent);
                    }
                }).start();
        }else{
            Toast.makeText(MainActivity.this, "Access Denied ! Cannot proceed further ", Toast.LENGTH_SHORT).show();
        }
    }
}

注意:显然，代码似乎在 StartupActivity 中(来自 StartupActivity.this)，因此您不需要创建线程，只需启动您的 详细信息 Activity 带有简单的Intent

---

代码将是

class StartupActivity extends ..{

    onCreate...(){}

    // here you will have onRequestPermissionsResult 
    @Override
    public void onRequestPermissionsResult( ....){...}

}