ios - HandleWatchKitExtensionRequest 中的嵌套 PFQuery

Question

我正在尝试将 2 个 PFQuery 嵌套在 HandleWatchKitExtensionRequest 中，以便我可以在回复中将数据传回我的 Watch Extension。在下面的代码中，第一个查询(对于匹配给定用户名的 PFUser)返回，但我无法让第二个(对于用户人员列表)返回。在同一个 block 中进行多个查询时，我缺少一些限制吗？在这个长时间运行的请求返回之前，我的后台任务是否超时？

*我编辑了我的代码，使 nameList 不是可选的，但仍然没有返回值。虽然同一个 block (嵌套的 findObjectsInBackGroundBlocks)在我的 IOS 应用程序中执行并完美返回。

延长后台任务的延迟时间没有帮助。

 func application(application: UIApplication, handleWatchKitExtensionRequest userInfo: [NSObject : AnyObject]?, reply: (([NSObject : AnyObject]!) -> Void)!) {


    var dictionary = userInfo! as NSDictionary


    if let currentUserName: AnyObject = dictionary.objectForKey("currentUserName") {
        if let currentUserNameAsString = currentUserName as? String {


            // Bogus task for keeping app going
            var bogusTask = UIApplication.sharedApplication().beginBackgroundTaskWithExpirationHandler { () -> Void in
            }
            // End bogus task after 2 seconds
            delay(2.0, closure: { () -> () in
                UIApplication.sharedApplication().endBackgroundTask(bogusTask)
            })

            // look up current user logged in on phone from name passed from Watch
            let query = PFUser.query()
            query!.whereKey("username", equalTo: currentUserNameAsString)
            query!.findObjectsInBackgroundWithBlock { (objects, error) -> Void in

                if let user = objects?.first as? PFUser {

                    var testName: String?
                    var nameList:  String = []
                    let query = PFQuery(className: Person.parseClassName())
                    query.whereKey("user", equalTo: user)

                    query.findObjectsInBackgroundWithBlock { (objects, error) -> Void in
                        if let people = objects as? [Person] {
                            for person in people {
                                if let name = person.name {
                                nameList.append(name)
                                    testName = nameList.first
                                }
                            }
                        }
                        testName = ("test")
                    }






                let testDict = ["success" : testName!]
                reply(testDict)

                 UIApplication.sharedApplication().endBackgroundTask(bogusTask) // End the bogusTask in case the work was faster than 2 seconds
                    }
                }


                }

            }




}

// Utility function for delay
func delay(delay:Double, closure:()->()) {
    dispatch_after(
        dispatch_time(
            DISPATCH_TIME_NOW,
            Int64(delay * Double(NSEC_PER_SEC))
        ),
        dispatch_get_main_queue(),
        closure
    )
}

Answer 1

看起来您在嵌套查询之外调用“reply(testDict)”。

由于查询是异步的，“reply(testDict)”可能在嵌套查询完成执行之前被调用。