ios - 在 Swift 3.0 中使用 XMPP 阻止和取消阻止用户

Question

我查看了很多有关在 Swift 中使用 XMPP 阻止和取消阻止用户的博客和网站。但是，没有一个例子对我有用。任何有代码段的人请与我分享。谢谢。

func blockUser(userJID: String) {
   let privacyList = XMPPPrivacy(dispatchQueue: DispatchQueue.main)
    privacyList?.activate(xmppStream)
    privacyList?.addDelegate(self, delegateQueue: DispatchQueue.main)

     let privacyElement = XMPPPrivacy.privacyItem(withType: "jid", value: userJID, action: "deny", order: 0)
    XMPPPrivacy.blockIQs(privacyElement)
    XMPPPrivacy.blockMessages(privacyElement)
    XMPPPrivacy.blockPresence(in: privacyElement)
}

Answer 1

您需要使用 XEP 0191用于阻止功能。

代码( swift 3.0):

     //Block / Unblock User

    var xmppBlocking: XMPPBlocking?

添加阻止用户和取消阻止用户

//Blocking Managment
    self.xmppBlocking = XMPPBlocking()
    self.xmppBlocking!.autoRetrieveBlockingListItems = true
    self.xmppBlocking!.autoClearBlockingListInfo = true;
    self.xmppBlocking!.addDelegate(self, delegateQueue: DispatchQueue.main)
    self.xmppBlocking!.activate(self.xmppStream)
    self.xmppBlocking?.retrieveBlockingListItems()

    xmppBlocking?.blockJID(user.jid) 
    xmppBlocking?.unblockJID(user.jid)



extension BlockListVC : XMPPBlockingDelegate{

        public func xmppBlocking(_ sender: XMPPBlocking!, didBlockJID xmppJID: XMPPJID!){
           //Successfully blocked
        }

        public func xmppBlocking(_ sender: XMPPBlocking!, didNotBlockJID xmppJID: XMPPJID!, error: Any!){
            if(error is NSError){
                //print error message
            }
        }

        public func xmppBlocking(_ sender: XMPPBlocking!, didReceivedBlockingList blockingList: [Any]!) {
            //Received blocked list in this delegate method
        }

   public func xmppBlocking(_ sender: XMPPBlocking!, didUnblockJID xmppJID: XMPPJID!) {

    }

    public func xmppBlocking(_ sender: XMPPBlocking!, didNotUnblockJID xmppJID: XMPPJID!, error: Any!) {
        if(error is NSError){

        }
    }
  }