Swift TensorFlowLite 解释器错误 : Type 'Interpreter' has no member 'Options'

Question

我从以下存储库中克隆了适用于 iOS 的 TensorFlowLite 示例应用程序 https://github.com/tensorflow/examples/tree/master/lite/examples/image_classification/ios

已安装的 pod 文件包含pod 'TensorFlowLiteSwift'

当我打开 ImageClassification.xcworkspace 时，Xcode 直接显示以下错误。

Type 'Interpreter' has no member 'Options'

我没有更改示例应用程序中的任何代码。

调用 Interpreter 的 Options() 时出现此错误

var options = Interpreter.Options()

我尝试使用 Interpreter 的其他方法获取 Option 属性，但无法获取。

init?(modelFileInfo: FileInfo, labelsFileInfo: FileInfo, threadCount: Int = 1) {
    let modelFilename = modelFileInfo.name

    // Construct the path to the model file.
    guard let modelPath = Bundle.main.path(
      forResource: modelFilename,
      ofType: modelFileInfo.extension
    ) else {
      print("Failed to load the model file with name: \(modelFilename).")
      return nil
    }

    // Specify the options for the `Interpreter`.
    self.threadCount = threadCount
    var options = Interpreter.Options() // Here the issue is *Type 'Interpreter' has no member 'Options*
    options.threadCount = threadCount
    do {
      // Create the `Interpreter`.
      interpreter = try Interpreter(modelPath: modelPath, options: options)
      // Allocate memory for the model's input `Tensor`s.
      try interpreter.allocateTensors()
    } catch let error {
      print("Failed to create the interpreter with error: \(error.localizedDescription)")
      return nil
    }
    // Load the classes listed in the labels file.
    loadLabels(fileInfo: labelsFileInfo)
  }

此 init() 应初始化并提供 ModelDataHandler 对象。

Answer 1

Interpreter.Options() 应该改回 InterpreterOptions() 它最初在所有 TensorFlow Lite 示例中的样子。

最近的一个提交破坏了构建: https://github.com/tensorflow/examples/commit/751f4648e3917178b0e67454422477fe5d81d611