ios - 点击时在 TableView 中为 ImageView 创建 subview 覆盖

Question

我想创建一个在 UITableView 上弹出的 subview ，其中包含全屏 cell 上的 UIImageView 图像在右上角有一个退出按钮，在另一个 cell 或 UITextView 底部有 cell 的 UITextView >

override func tableView(tableView: UITableView, cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell {
    let cell = tableView.dequeueReusableCellWithIdentifier(reuseIdentifier, forIndexPath: indexPath) as! TalesTableViewCell let tapGesture = UITapGestureRecognizer(target: self, action: "imageTapped:")

    cell.tableImage.addGestureRecognizer(tapGesture)

    cell.tableImage.userInteractionEnabled = true

    return cell
}

func imageTapped(gesture: UIGestureRecognizer) {

    //Code here I think

}

有什么想法吗？谢谢!

Answer 1

使用下面的代码..

func imageTapped(gesture: UIGestureRecognizer) {

    var overlay : UIView = UIView(frame: CGRectMake(0, 0, self.view.frame.size.width, self.view.frame.size.height))

    var imageView : UIImageView = UIImageView(image: (gesture.view as! UIImageView).image) // This includes your image in table view cell

    imageView.frame = CGRectMake(0, 0, 0, 0) // set up according to your requirements

    var doneBtn : UIButton = UIButton(frame: CGRectMake(0, 0, 0, 0)) // set up according to your requirements
    doneBtn.addTarget(self, action: "pressed:", forControlEvents: .TouchUpInside)

    overlay.addSubview(imageView)
    overlay.addSubview(doneBtn)

    self.view.addSubview(overlay)
}

func pressed(sender: UIButton!) {

    sender.superview?.removeFromSuperview()
}