ios - 在 XCode 中随机化颜色

Question

我正在尝试使用我已经创建的一些颜色随机化 XCode 中标签的文本颜色，我尝试了不同的方法，这是我得到的最接近的方法。

    override func viewDidLoad() {
    super.viewDidLoad()

    let color1 = UIColor(red: 1, green: 165/255, blue: 0, alpha: 1)
    let color2 = UIColor(red: 80/255, green: 1, blue: 200/255, alpha: 1)
    let color3 = UIColor(red: 150/255, green: 80/255, blue: 1, alpha: 1)
    let color4 = UIColor(red: 1, green: 80/255, blue: 80/255, alpha: 1)
    let color5 = UIColor(red: 80/255, green: 1, blue: 80/255, alpha: 1)

    var randomEight = arc4random_uniform(5)+1
    var randomColor:String = String(format:"color%i", randomEight)

    randomLabel.textColor = randomColor
}

但是，randomColor 变量是一个字符串，我无法将它转换为 UIColor。

Answer 1

将所有颜色放在一个数组中，然后使用 randomEight 作为数组中的索引以获得正确的颜色。此外，您可能需要检查整数除法以确保获得正确的颜色。

let color1 = UIColor(red: 1, green: 165/255, blue: 0, alpha: 1)
let color2 = UIColor(red: 80/255, green: 1, blue: 200/255, alpha: 1)
let color3 = UIColor(red: 150/255, green: 80/255, blue: 1, alpha: 1)
let color4 = UIColor(red: 1, green: 80/255, blue: 80/255, alpha: 1)
let color5 = UIColor(red: 80/255, green: 1, blue: 80/255, alpha: 1)

let colors = [color1, color2, color3, color4, color5]
let randomEight = Int(arc4random_uniform(UInt32(colors.count)))

randomLabel.textColor = colors[randomEight]