ios - 如何将 NSInputStream 转换为 UIImage

Question

我有一个要发送到服务器的 NSInputStream，在上传过程中，我想显示正在上传的图像。方法位于单例中，它正在接收 NSInputStream。有没有办法读取该流并将其转换为 UIImage？

我试过这个，但没有成功。我的错误在哪里？

var buffer = [UInt8](count:1024, repeatedValue: 0)
    thumbnailStream.open()
    if (thumbnailStream.hasBytesAvailable){
        let len : Int = inputStream.read(&buffer, maxLength: buffer.count)
        var pictureData = NSData(bytes: buffer, length: len)
        var imagess = UIImage(data: pictureData)!
        self.headerProgress.imageView.image = imagess
        print("Data of image = \(pictureData.length)")

        }else{
        print("No bytes")
    }

谢谢!

Answer 1

我已经找到了这个问题的解决方案，并且可以正常工作。

    var count = 0
    let dataOfTheImage = NSMutableData()
    var buffer = [UInt8](count:1024, repeatedValue: 0)
    thumbnailStream.open()

    //MARK: Loop through thumbnail stream
    while (thumbnailStream.hasBytesAvailable){
        count = count + 1
        print("Counter: \(count)")
        //MARK: Read from the stream and append bytes to NSMutableData variable
        let len  = thumbnailStream.read(&buffer, maxLength: buffer.count)
        dataOfTheImage.appendBytes(buffer, length: len)

        //MARK: Size of the image in MB
        let size = Float(dataOfTheImage.length) / 1024.0 / 1024.0
        print("Data length = \(size)")
    }

    //MARK: Check if there are no bytes left and show the image
    if (thumbnailStream.hasBytesAvailable == false){
        thumbnailStream.close()
       // var pictureData = NSData(bytes: buffer, length: len)
        let progressImage = UIImage(data: dataOfTheImage)!
        dispatch_async(dispatch_get_main_queue(), {() -> Void in
            self.headerProgress.imageView.image = progressImage
        })
    }