ios - 使用 `UIActivityItemSource` 协议(protocol)无法分享到 Instagram

Question

我使用 UIActivityViewController 共享文本和图像。该图像来自 activityImage，它是一个 UIImage()。自定义文本来自 activityText()，它是从 UIActivityItemSource 协议(protocol)返回的。

问题是，Instagram 仅在特定条件下在 UIActivityViewController 中可见。

汇总以下测试:

• Instagram 仅在 UIActivityViewController 中可见 activityItems: [activityImage] 和 activityItems: [activityImage, NSNull ()]

• Instagram 为 activityItems: [activityImage, activityText()] 隐藏 即使返回的 UIActivityItemSource 协议(protocol)值为 "", nil, NSNull()。

问题是需要调用UIActivityItemSource协议(protocol)，这样才能对不同的分享平台进行单独管理。

---

Questions:

• How can I share to Instagram when calling the UIActivityItemSource protocol?

• What are the alternatives to "", nil and NSNull() that I could try when calling the UIActivityItemSource protocol?

---

代码:

class activityText: NSObject, UIActivityItemSource {
    @objc func activityViewControllerPlaceholderItem(activityViewController: UIActivityViewController) -> AnyObject {
        return ""
    }
    @objc func activityViewController(activityViewController: UIActivityViewController, itemForActivityType activityType: String) -> AnyObject? {
        switch activityType {
        case UIActivityTypeMessage:
            return "Special text when sharing to Messages."
        default:
            return ""
        }
    }
}

func shareEverwhere() {
      var activityImage: UIImage() 
      let activity = UIActivityViewController(activityItems: [activityImage, activityText()], applicationActivities: nil)
      self.presentViewController(activity, animated: true, completion: nil)
}

---

测试:

Instagram 在 UIActivityViewController 中可见

let activity = UIActivityViewController(activityItems: [activityImage], applicationActivities: nil)

或

let activity = UIActivityViewController(activityItems: [activityImage, NSNull()], applicationActivities: nil)

Instagram 隐藏在UIActivityViewController

let activity = UIActivityViewController(activityItems: [activityImage, ""], applicationActivities: nil)

或

let activity = UIActivityViewController(activityItems: [activityImage, activityText()], applicationActivities: nil)

或

let activity = UIActivityViewController(activityItems: [activityImage, activityText()], applicationActivities: nil)
class activityText: NSObject, UIActivityItemSource {
    @objc func activityViewControllerPlaceholderItem(activityViewController: UIActivityViewController) -> AnyObject {
        return ""
    }
    @objc func activityViewController(activityViewController: UIActivityViewController, itemForActivityType activityType: String) -> AnyObject? {
        return NSNull()
    }
}

或

let activity = UIActivityViewController(activityItems: [activityImage, activityText()], applicationActivities: nil)
class activityText: NSObject, UIActivityItemSource {
    @objc func activityViewControllerPlaceholderItem(activityViewController: UIActivityViewController) -> AnyObject {
        return ""
    }
    @objc func activityViewController(activityViewController: UIActivityViewController, itemForActivityType activityType: String) -> AnyObject? {
            return nil
    }
}

或

let activity = UIActivityViewController(activityItems: [activityImage, activityText()], applicationActivities: nil)
class activityText: NSObject, UIActivityItemSource {
    @objc func activityViewControllerPlaceholderItem(activityViewController: UIActivityViewController) -> AnyObject {
        return ""
    }
    @objc func activityViewController(activityViewController: UIActivityViewController, itemForActivityType activityType: String) -> AnyObject? {
            return ""
    }
}

Answer 1

在以下位置提出并回答了问题:Share image with hashtag via UIActivityViewController (Twitter, Facebook, Instagram)

        UIActivityViewController *activityViewController =
 [[UIActivityViewController alloc] initWithActivityItems:@[vm.image, [[ActivityStringItemSource alloc] initWithString:attributedString]] applicationActivities:nil];

实现字符串返回(或不返回)的类是:

@interface ActivityStringItemSource()<UIActivityItemSource>

@property(strong, nonatomic) NSMutableAttributedString *stringContent;
@end

@implementation ActivityStringItemSource

- (instancetype)initWithString:(NSMutableAttributedString *) placeholder
{
    self = [super init];
    if (self) {
        _stringContent = placeholder;
    }
    return self;
}

- (id)activityViewControllerPlaceholderItem:(UIActivityViewController *)activityViewController {
    return [NSObject new];
}

- (id)activityViewController:(UIActivityViewController *)activityViewController itemForActivityType:(UIActivityType)activityType {
    if([activityType containsString:@"instagram"]) {
        return nil;
    } else {
        return _stringContent;
    }
}

@end

正如原始答案所指出的那样，关键是返回一个 NSObject(该类扩展了 NSObject)。然后在项目选择中，只需测试 instagram 以返回 nil，否则返回您的字符串。