ios - 实例成员 'showSettings' 不能用于类型 'SettingsLauncher'

Question

我正试图将按钮中的一大堆代码移动到一个文件中。这是我原来的 VC 中的按钮

    let blackView = UIView()
    let settingsLuancher = SettingsLauncher()

    @IBAction func refreshBtnAction(_ sender: UIButton) {

      SettingsLauncher.showSettings()

    }

这是 SettingsLauncher.swift，

import Foundation
import UIKit

class SettingsLauncher:NSObject {

let blackView = UIView()

func showSettings() {
    if let window = UIApplication.shared.keyWindow{
        blackView.backgroundColor = UIColor(white: 0, alpha: 0.5)
        window.addSubview(blackView)
        blackView.frame = window.frame
        blackView.alpha = 0

        blackView.addGestureRecognizer(UITapGestureRecognizer(target: self, action: #selector(handleDismiss)))

        UIView.animate(withDuration: 0.2, animations: {
            self.blackView.alpha = 1
        })
    }

}

func handleDismiss(){
    UIView.animate(withDuration: 0.2, animations: {
        self.blackView.alpha = 0
        // dismisses blackView
    })
}

编译一直失败并显示:实例成员“showSettings”不能用于类型“SettingsLauncher”；您是想改用这种类型的值吗？

不知道为什么会这样，感谢任何帮助。

Answer 1

查看 SettingsLauncher.showSettings() 它不是类方法，它是实例方法，因此它将被类的实例而不是类本身调用。

像下面一样

settingsLuancher.showSettings()