swift - 在分组字典中对子数组进行排序

Question

我有 3 个数组，我必须在同一年合并它们。我已经这样做了，然后我使用 Dictionary.init(grouping: weatherDataArray) 进行了分组，现在我正在尝试对分组字典进行排序。这是我拥有的数据示例:

[2008: [["year": 2008, "month": 12, "rainfallValue": 87.9000015, "tminValue": 0.200000003, "tmaxValue": 6.0999999], ["year": 2008, "month": 11, "rainfallValue": 106.400002, "tminValue": 0.200000003, "tmaxValue": 6.0999999], ["year": 2008, "month": 10, "rainfallValue": 155.699997, "tminValue": 0.200000003, "tmaxValue": 6.0999999], ["year": 2008, "month": 9, "rainfallValue": 106.300003, "tminValue": 0.200000003, "tmaxValue": 6.0999999], ["year": 2008, "month": 8, "rainfallValue": 133.600006, "tminValue": 0.200000003, "tmaxValue": 6.0999999], ["year": 2008, "month": 7, "rainfallValue": 108.099998, "tminValue": 0.200000003, "tmaxValue": 6.0999999], ["year": 2008, "month": 6, "rainfallValue": 78.5, "tminValue": 0.200000003, "tmaxValue": 6.0999999], ["year": 2008, "month": 5, "rainfallValue": 47.9000015, "tminValue": 0.200000003, "tmaxValue": 6.0999999], ["year": 2008, "month": 4, "rainfallValue": 76.1999969, "tminValue": 0.200000003, "tmaxValue": 6.0999999], ["year": 2008, "month": 3, "rainfallValue": 122.5, "tminValue": 0.200000003, "tmaxValue": 6.0999999], ["year": 2008, "month": 2, "rainfallValue": 82.3000031, "tminValue": 0.200000003, "tmaxValue": 6.0999999], ["year": 2008, "month": 1, "rainfallValue": 189.600006, "tminValue": 0.200000003, "tmaxValue": 6.0999999]], 1992: [["year": 1992, "month": 6, "rainfallValue": 38.5999985, "tminValue": 3.20000005, "tmaxValue": 5.80000019], ["year": 1992, "month": 5, "rainfallValue": 57.2999992, "tminValue": 3.20000005, "tmaxValue": 5.80000019], ["year": 1992, "month": 4, "rainfallValue": 88.0, "tminValue": 3.20000005, "tmaxValue": 5.80000019], ["year": 1992, "month": 3, "rainfallValue": 125.0, "tminValue": 3.20000005, "tmaxValue": 5.80000019], ["year": 1992, "month": 2, "rainfallValue": 87.5, "tminValue": 3.20000005, "tmaxValue": 5.80000019], ["year": 1992, "month": 1, "rainfallValue": 77.4000015, "tminValue": 3.20000005, "tmaxValue": 5.80000019], ["year": 1992, "month": 12, "rainfallValue": 105.0, "tminValue": 3.20000005, "tmaxValue": 5.80000019], ["year": 1992, "month": 11, "rainfallValue": 158.5, "tminValue": 3.20000005, "tmaxValue": 5.80000019], ["year": 1992, "month": 10, "rainfallValue": 94.5, "tminValue": 3.20000005, "tmaxValue": 5.80000019], ["year": 1992, "month": 9, "rainfallValue": 115.5, "tminValue": 3.20000005, "tmaxValue": 5.80000019], ["year": 1992, "month": 8, "rainfallValue": 157.300003, "tminValue": 3.20000005, "tmaxValue": 5.80000019], ["year": 1992, "month": 7, "rainfallValue": 84.1999969, "tminValue": 3.20000005, "tmaxValue": 5.80000019]]]

基本上是 [Int: [[String: Any]]] 类型。

所以我得到的组是年，我的目标是制作一个按年和月按升序顺序排序的数组，基本上[[String: Any]] 这将首先显示 1992 年的数据，月份将从 1-12 开始，然后是 2008 年以及与今年相关的月份从 1-12 开始。

下一步应该做什么？或者是否有不同的方法来做到这一点？

Answer 1

您可以先根据键对分组字典进行排序，这样您就可以得到一个按年份排序的元组数组，然后对其调用 map 并返回值，即字典数组，并根据月份在 map 调用中对它们进行排序。

我将你问题中的值存储在 groupedDict 中。

let sortedArrFromDict = groupedDict.sorted(by: {$0.key < $1.key}).flatMap({$0.value.sorted(by: {$0["month"]! < $1["month"]!})})
print(sortedArrFromDict)