ios - Swift 中的泛型选择器 View

Question

我正在尝试使用 Generics 创建一个通用的 UI Picker。作为我实现的一部分，我创建了要在 UIPicker 中显示的 GenericRow 对象。但我面临一些问题。它可能是基本的，但找不到。

struct GenericRow<T> {
    let type: T
    let title: String
    public init(type: T, title: String) {
        self.type = type
        self.title = title
    }
 }

接下来是处理 UIPickerViewDataSource 和 UIPickerViewDelegate 的 GenericDataSource。

class GenericPickerDataSource<T>: NSObject, UIPickerViewDelegate, UIPickerViewDataSource {

    public var items: [GenericRow<T>]

    public init(withItems items: [GenericRow<T>]) {
        self.items = items
    }

    public func numberOfComponents(in pickerView: UIPickerView) -> Int {
        return 1
    }

    public func pickerView(_ pickerView: UIPickerView, numberOfRowsInComponent component: Int) -> Int {
        return items.count
    }

    public func pickerView(_ pickerView: UIPickerView, titleForRow row: Int, forComponent component: Int) -> String? {
        return items[row].title
    }
}

然后，我正在创建一个管理器来处理选择器显示/隐藏功能。请注意，这也是通用的，并且对 GenericRow 类型一无所知。

class GenericPickerManager {
    static func showPicker(_ dataSource: GenericPickerDataSource<Any>) {}

    static func hidePicker() {}
}

示例输入:

struct State {
    let identifier: String
    let name: String
}

let CA = State(identifier: "CA", name: "California")
let CLT = State(identifier: "CLT", name: "Charlotte")
let IL = State(identifier: "IL", name: "Illinois")

let states = [CA, CLT, IL]

let items = states.map {
    GenericRow<State>(type: $0, title: $0.name)
}

let dataSource = GenericPickerDataSource(withItems: items)

现在，当我尝试显示我类(class)的选择器时，出现错误。

GenericPickerManager.showPicker(dataSource)

Cannot convert value of type GenericPickerDataSource<State> to expected argument type GenericPickerDataSource<Any>.

如何解决这个问题？

Answer 1

Any 和泛型不能很好地协同工作。使 GenericPickerManager 也通用:

class GenericPickerManager<T> {
    static func showPicker(_ dataSource: GenericPickerDataSource<T>) {}

    static func hidePicker() {}
}