arrays - 搜索值数组以在字典中查找键

Question

我有一个字典，例如:

let dict = ["1" : ["one","une"],
            "2" : ["two","duex"]]

我正在使用以下代码来搜索值以获取 key 。例如，如果我搜索“one”，我将返回“1”。

let searchIndex = dict.firstIndex(where: { $0.value.contains("one") })

if let index = searchIndex {
  print("Return: \(dict[index].key)") // prints "1"    
} else {
  print("Could not find")
}

但是，这仅在我搜索完全匹配的字符串时有效。我如何才能仅通过搜索字符串的一部分来返回匹配的键。换句话说，如果我搜索“on”，它不会返回“1”。

Answer 1

你可以这样做:

let dict = ["1" : ["one","une"],
            "2" : ["two","deux"],
            "11": ["eleven, onze"]]

let searchText = "on"

let goodKeys = dict.keys.filter { key in
    dict[key]!.contains { word in
        return word.contains(searchText)
    }
}

print(goodKeys)     //["1", "11"]

---

在回答您的评论时，这里有一个解决方案:

let searchText = "one une"
let components = searchText.components(separatedBy: " ")

let goodKeys = dict.keys.filter { key in
    dict[key]!.contains { word in
        return components.contains { component in
            word.contains(component)
        }
    }
}

print(goodKeys)     //["1"]