ios - Swift:在没有 key 的情况下解析 JSON 字符串

Question

我想解析 json 字符串如下，我想知道如何打印 [times] 值

Json 字符串:

{
date: "2014-08-13",
method: "Makkah: Umm al-Qura University, Makkah",
latitude: "30.0599153",
longtude: "31.2620199",
timezone: "+3",
times: [
"04:52",
"06:21",
"13:00",
"16:36",
"19:38",
"19:38",
"21:08"
] }

这是我的代码:

let json = try NSJSONSerialization.JSONObjectWithData(data!, options:.AllowFragments)

                let todayDate = json["date"]
                let method = json["method"]
                let latitude = json["latitude"]
                let longtude = json["longtude"]
                let timezone = json["timezone"]

所以问题是，如何打印时间，谢谢

Answer 1

let times = json["times"] as! [String]

for time in times {
   print(time) 
}

或在一行中

times.forEach{ print($0) }