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ios - 如何在 Swift 中将 UIColor 转换为 3/4/6/8 位十六进制字符串?

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如何在 Swift 中将 UIColor 转换为 3/4/6/8 位的十六进制字符串?

我如何获得特定的?例如,通过调用 UIColor.blue.eightDigitsString

获取“#0000FFFF”

请参阅this :

5.2. The RGB hexadecimal notations: #RRGGBB

The CSS hex color notation allows a color to be specified by giving the channels as hexadecimal numbers, which is similar to how colors are often written directly in computer code. It’s also shorter than writing the same color out in rgb() notation.

The syntax of a is a <hash-token> token whose value consists of 3, 4, 6, or 8 hexadecimal digits. In other words, a hex color is written as a hash character, "#", followed by some number of digits 0-9 or letters a-f (the case of the letters doesn’t matter - #00ff00 is identical to #00FF00).

The number of hex digits given determines how to decode the hex notation into an RGB color:

6 digits
The first pair of digits, interpreted as a hexadecimal number, specifies the red channel of the color, where 00 represents the minimum value and ff (255 in decimal) represents the maximum. The next pair of digits, interpreted in the same way, specifies the green channel, and the last pair specifies the blue. The alpha channel of the color is fully opaque. In other words, #00ff00 represents the same color as rgb(0 255 0) (a lime green).

8 digits
The first 6 digits are interpreted identically to the 6-digit notation. The last pair of digits, interpreted as a hexadecimal number, specifies the alpha channel of the color, where 00 represents a fully transparent color and ff represent a fully opaque color. In other words, #0000ffcc represents the same color as rgb(0 0 100% / 80%) (a slightly-transparent blue).

3 digits
This is a shorter variant of the 6-digit notation. The first digit, interpreted as a hexadecimal number, specifies the red channel of the color, where 0 represents the minimum value and f represents the maximum. The next two digits represent the green and blue channels, respectively, in the same way. The alpha channel of the color is fully opaque. This syntax is often explained by saying that it’s identical to a 6-digit notation obtained by "duplicating" all of the digits. For example, the notation #123 specifies the same color as the notation #112233. This method of specifying a color has lower "resolution" than the 6-digit notation; there are only 4096 possible colors expressible in the 3-digit hex syntax, as opposed to approximately 17 million in 6-digit hex syntax.

4 digits
This is a shorter variant of the 8-digit notation, "expanded" in the same way as the 3-digit notation is. The first digit, interpreted as a hexadecimal number, specifies the red channel of the color, where 0 represents the minimum value and f represents the maximum. The next three digits represent the green, blue, and alpha channels, respectively.

现在我已经知道如何将 UIColor 对象转换为 6 位十六进制字符串。但我不确定如何将其转换为 3 位/4 位/8 位十六进制字符串以及应该注意什么。

guard let components = cgColor.components, components.count >= 3 else {
return nil
}
let r = Float(components[0])
let g = Float(components[1])
let b = Float(components[2])
var a = Float(1.0)
if components.count >= 4 {
a = Float(components[3])
}
if alpha {
// rrggbbaa mode
// is there any difference between rrggbbaa and aarrggbb?
return String(format: "%02lX%02lX%02lX%02lX", lroundf(r * 255), lroundf(g * 255), lroundf(b * 255), lroundf(a * 255))
} else {
// rrggbb mode
return String(format: "%02lX%02lX%02lX", lroundf(r * 255), lroundf(g * 255), lroundf(b * 255))
}

注意:是UIColor转字符串,不是字符串转UIColor

最佳答案

这是 UIColor 的扩展,它可以提供多种格式的 hexString,包括 3、4、6 和 8 位数字形式:

extension UIColor {
enum HexFormat {
case RGB
case ARGB
case RGBA
case RRGGBB
case AARRGGBB
case RRGGBBAA
}

enum HexDigits {
case d3, d4, d6, d8
}

func hexString(_ format: HexFormat = .RRGGBBAA) -> String {
let maxi = [.RGB, .ARGB, .RGBA].contains(format) ? 16 : 256

func toI(_ f: CGFloat) -> Int {
return min(maxi - 1, Int(CGFloat(maxi) * f))
}

var r: CGFloat = 0
var g: CGFloat = 0
var b: CGFloat = 0
var a: CGFloat = 0

self.getRed(&r, green: &g, blue: &b, alpha: &a)

let ri = toI(r)
let gi = toI(g)
let bi = toI(b)
let ai = toI(a)

switch format {
case .RGB: return String(format: "#%X%X%X", ri, gi, bi)
case .ARGB: return String(format: "#%X%X%X%X", ai, ri, gi, bi)
case .RGBA: return String(format: "#%X%X%X%X", ri, gi, bi, ai)
case .RRGGBB: return String(format: "#%02X%02X%02X", ri, gi, bi)
case .AARRGGBB: return String(format: "#%02X%02X%02X%02X", ai, ri, gi, bi)
case .RRGGBBAA: return String(format: "#%02X%02X%02X%02X", ri, gi, bi, ai)
}
}

func hexString(_ digits: HexDigits) -> String {
switch digits {
case .d3: return hexString(.RGB)
case .d4: return hexString(.RGBA)
case .d6: return hexString(.RRGGBB)
case .d8: return hexString(.RRGGBBAA)
}
}
}

示例

print(UIColor.red.hexString(.d3))  // #F00
print(UIColor.red.hexString(.d4)) // #F00F
print(UIColor.red.hexString(.d6)) // #FF0000
print(UIColor.red.hexString(.d8)) // #FF0000FF

print(UIColor.green.hexString(.RGB)) // #0F0
print(UIColor.green.hexString(.ARGB)) // #F0F0
print(UIColor.green.hexString(.RGBA)) // #0F0F
print(UIColor.green.hexString(.RRGGBB)) // #00FF00
print(UIColor.green.hexString(.AARRGGBB)) // #FF00FF00
print(UIColor.green.hexString(.RRGGBBAA)) // #00FF00FF

print(UIColor(red: 0.25, green: 0.5, blue: 0.75, alpha: 0.3333).hexString()) // #4080c055

关于ios - 如何在 Swift 中将 UIColor 转换为 3/4/6/8 位十六进制字符串?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/50264610/

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