swift - 如何在swift中设置嵌套？

Question

三套以下如何做一套？ .我的意思是一个嵌套集

var nameSets : Set<String> = ["Nazmul","Hasan","Prince"]
var countrySets : Set<String> = ["UK","London","Bangladesh"]
var securitys : Set<Int> = [2904,99895,8944]

//work
var addresSets : Set = [nameSet,countrySet] 
//cannot convert value of type '[Any]' to specified type 'Set'
 var addresSets : Set = [nameSet,countrySet,security]
// type 'Any' does not conform to protocol 'Hashable'
var addresSets : Set<Any> = [nameSet,countrySet,security]

Answer 1

我不确定你想在这里实现什么，但是首先让我们清理你的代码

let names: Set = ["Nazrul", "Hasan", "Prince"]
let countries: Set = ["UK", "London", "Bangladesh"]
let securities: Set = [2904, 99895, 8944]

我们有 2 Set(s)的 String和 1 Set的 Int .

名字和国家

现在让我们创建一个包含names 的新集合。和 countries .

let all: Set = [names, countries]

all 的推断类型是Set<Set<String>> .

名称、国家和证券

让我们改变一下all现在有人居住

let all: Set = [names, countries, securities]
error: argument type 'Set<_>' does not conform to expected type 'Any'

现在编译器需要一点帮助来弄清楚 all应该定义。正确的定义是Set<Set<AnyHashable>>所以

let all: Set<Set<AnyHashable>> = [names, countries, securities]

结果

现在all包含 3 个原件 Set(s) .

[
    Set([AnyHashable(99895), AnyHashable(8944), AnyHashable(2904)]),
    Set([AnyHashable("Nazmul"), AnyHashable("Prince"), AnyHashable("Hasan")]),
    Set([AnyHashable("London"), AnyHashable("Bangladesh"), AnyHashable("UK")])
]