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ios - 如何从 API 调用中获取原始 JSON

转载 作者:搜寻专家 更新时间:2023-11-01 05:55:08 25 4
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[注意:为了清晰起见,已经对本文进行了编辑,因为我想要的似乎有些困惑。我想要原始 JSON。在这种情况下,它应该是 {"foo":"bar"}。重要的是要强调我想要它作为一个字符串!我不需要将它解码为 Swift 对象或以任何方式编码或修改!]

是否可以从 API 调用中获取原始 JSON?目前我正在使用 URLSession.dataTask(with:request) 但响应数据包括响应 header 和正文。我只想要返回给我的原始 JSON,作为字符串。

这是我使用的代码:

// Build the URL
var urlComponents = URLComponents()
urlComponents.scheme = "http"
urlComponents.host = "127.0.0.1"
urlComponents.port = 80
urlComponents.queryItems = [URLQueryItem(name: "foo", value: "bar")]
guard let url = urlComponents.url else {
fatalError("Could not create URL from components")
}

// Configure the request
var request = URLRequest(url: url)
request.httpMethod = "GET"
request.addValue("application/json", forHTTPHeaderField: "Content-Type")
request.addValue("application/json", forHTTPHeaderField: "Accept")

let task = URLSession.shared.dataTask(with: request) {(responseData, response, error) in
DispatchQueue.main.async {
guard error == nil else {
print("ERROR: \(String(describing: error))")
return
}

guard let _ = response else {
print("Data was not retrieved from request")
return
}

print("JSON String: \(String(describing: String(data: responseData!, encoding: .utf8)))")

if let resData = responseData {
let jsonResponse = try? JSONSerialization.jsonObject(with: resData, options: [])

if let response = jsonResponse as? [String: Any] {
print("RESPONSE:")
dump(response)
} else {
print("SOMETHING WENT WRONG")
}
}
}
}

task.resume()

这会在控制台中产生以下内容:

JSON String: Optional("HTTP/1.1 OK\nContent-Type: application/json\n\n{\"foo\":\"bar\"}")
SOMETHING WENT WRONG

最佳答案

您将在完成处理程序 Data 参数中找到响应主体。您可以决定要用它做什么。

let task = session.dataTask(with: request) { (responseData, response, responseError) in
guard responseData = responseData else { return }
print("JSON String: \(String(data: responseData, encoding: .utf8))")
}

关于ios - 如何从 API 调用中获取原始 JSON,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/50341111/

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