ios - 使用 Alamofire 的 responseSerializationFailed

Question

import UIKit
import Alamofire
import SwiftyJSON

class LoginViewController: UIViewController {


    @IBOutlet weak var urlTextFiled: UITextField!
    @IBOutlet weak var emailTextFiled: UITextField!
    @IBOutlet weak var passwordTextFiled: UITextField!

    override func viewDidLoad() {
        super.viewDidLoad()
    }

    override func didReceiveMemoryWarning() {
        super.didReceiveMemoryWarning()

    }

        guard let email = emailTextFiled.text, !email.isEmpty else {
            return
        }
        guard let password = passwordTextFiled.text, !password.isEmpty else {
            return
        }
        let db = "mohanad"
        let url = "http://176.58.117.249/web/session/authenticate"

        let parameters: [String: Any] = [
        "db": db,
        "login": email,
        "password": password ,
        ]

        Alamofire.request(url, method: .post, parameters: parameters, encoding: URLEncoding.default, headers: nil)
        .validate(statusCode: 200..<600)
        .responseJSON { response in

            switch response.result
            {
            case .failure(let error):
                print(error)

            case .success(let value):

                print(value)
            }

        }


    }

}

打印以下错误:

responseSerializationFailed(Alamofire.AFError.ResponseSerializationFailureReason.jsonSerializationFailed(Error Domain=NSCocoaErrorDomain Code=3840 "Invalid value around character 0." UserInfo={NSDebugDescription=Invalid value around character 0.}))

Answer 1

用 .responseString 替换 .responseJSON 所以:

代替:

Alamofire.request(url, method: .post, parameters: parameters, encoding: URLEncoding.default, headers: nil).responseJSON
{ response in
      //....                
}

做:

Alamofire.request(url, method: .post, parameters: parameters, encoding: URLEncoding.default, headers: nil).responseString
{ response in
     //....       
}