gpt4 book ai didi

javascript - Javascript Fancy 树中根节点的完整路径

转载 作者:搜寻专家 更新时间:2023-11-01 05:23:17 24 4
gpt4 key购买 nike

我正在使用 Fancy tree 来填充树,以便理解显示的代码

 var treeData = [{"title":"image_test","folder":true,"children":[{"title":"images5","folder":true,"children":[{"title":"img_01.png","children":[]},{"title":"img_02.png","children":[]},{"title":"img_03.png","children":[]},{"title":"img_04.png","children":[]},{"title":"img_05.png","children":[]},{"title":"img_06.png","children":[]},{"title":"img_07.png","children":[]}]},{"title":"images4","folder":true,"children":[{"title":"img_01.png","children":[]},{"title":"img_02.png","children":[]},{"title":"img_03.png","children":[]},{"title":"img_04.png","children":[]},{"title":"img_05.png","children":[]},{"title":"img_06.png","children":[]},{"title":"img_07.png","children":[]}]},{"title":"images3","folder":true,"children":[{"title":"img_01.png","children":[]},{"title":"img_02.png","children":[]},{"title":"img_03.png","children":[]},{"title":"img_04.png","children":[]},{"title":"img_05.png","children":[]},{"title":"img_06.png","children":[]},{"title":"img_07.png","children":[]}]},{"title":"images2","folder":true,"children":[{"title":"img_01.png","children":[]},{"title":"img_02.png","children":[]},{"title":"img_03.png","children":[]},{"title":"img_04.png","children":[]},{"title":"img_05.png","children":[]},{"title":"img_06.png","children":[]},{"title":"img_07.png","children":[]}]},{"title":"images1","folder":true,"children":[{"title":"img_01.png","children":[]},{"title":"img_02.png","children":[]},{"title":"img_03.png","children":[]},{"title":"img_04.png","children":[]},{"title":"img_05.png","children":[]},{"title":"img_06.png","children":[]},{"title":"img_07.png","children":[]}]}]}];


$(function(){
$("#tree3").fancytree({
// extensions: ["select"],
checkbox: true,
selectMode: 3,
source: treeData,
select: function(event, data) {
// Get a list of all selected nodes, and convert to a key array:
var selKeys = $.map(data.tree.getSelectedNodes(), function(node){
return node.key;
});
$("#echoSelection3").text(selKeys.join(", "));

// Get a list of all selected TOP nodes
var selRootNodes = data.tree.getSelectedNodes(true);
// ... and convert to a key array:
var selRootKeys = $.map(selRootNodes, function(node){
return node.key;
});
$("#echoSelectionRootKeys3").text(selRootKeys.join(", "));
$("#echoSelectionRoots3").text(selRootNodes.join(", "));
},
dblclick: function(event, data) {
data.node.toggleSelected();
},
keydown: function(event, data) {
if( event.which === 32 ) {
data.node.toggleSelected();
return false;
}
},
// The following options are only required, if we have more than one tree on one page:
// initId: "treeData",
cookieId: "fancytree-Cb3",
idPrefix: "fancytree-Cb3-"
});
});

使用的div是tree3。

<div id="tree3"></div>
<div>Selected keys: <span id="echoSelection3">-</span></div>
<div>Selected root keys: <span id="echoSelectionRootKeys3">-</span></div>
<div>Selected root nodes: <span id="echoSelectionRoots3">-</span></div></div>

现在我希望每当用户检查子节点时,父节点的名称,直到根节点也显示出来,我已经使用了

var selRootNodes = data.tree.getSelectedNodes(true);

但无法在回声选择中获得结果作为子节点,然后直到根节点

实际上我想将选择发送到服务器以便保存它们,因为它们是文件路径。

由于我是第一次使用树种群,所以请多多包涵。如果有任何其他好的选择,请提供。

附言;我想以目录地址/abc/acv/ac/xyz.png 的形式将树路径发送到服务器 image is attached which is not showing image5 and image_test in the selected root nodes

最佳答案

在搜索并深入研究代码后,我找到了解决方案:

 $(function(){

var tree3 = $("#tree3").fancytree({
checkbox: true,
selectMode: 3,
source: $.ajax({
url: "/getlist",
dataType: "json"
}),
select: function(event, data) {

// Get a list of all selected nodes, and convert to a key array:
var selKeys =
$.map(data.tree.getSelectedNodes(), function(node) {
if(node.key != 0){
return node.key;
}
});

var rootstructures =
$.map(selKeys, function(item){
var tempnode = data.tree.getNodeByKey(item);
var tempstructure = [];
tempstructure.push(data.tree.getNodeByKey(item).title);
while(tempnode.getParent().getParent()){
tempstructure.push(tempnode.getParent().title);
tempnode = tempnode.getParent();
}
tempstructure.reverse();
return tempstructure.join('/');
});

// WRITE DEBUG OUTPUT TO DIVS

$("#echoSelectionRoots4").text(rootstructures);
$("#echoSelection3").text(selKeys.join(", "));

// Get a list of all selected TOP nodes
var selRootNodes = data.tree.getSelectedNodes(true);
// ... and convert to a key array:
var selRootKeys = $.map(selRootNodes, function(node){
return node.key;
});
$("#echoSelectionRootKeys3").text(selRootKeys.join(", "));
$("#echoSelectionRoots3").text(selRootNodes.join(", "));

// -----------------

},
});
});

此实现有效,现在选择路径,直到根节点填充到 echoSelectionRoots4 对象上。

示例输出:/image_test/image5/img_01.png,/image_test/image5/img_02.png 等

关于javascript - Javascript Fancy 树中根节点的完整路径,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/22355936/

24 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com