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javascript - 如何在 jquery 中对规则进行分组

转载 作者:搜寻专家 更新时间:2023-11-01 04:11:47 25 4
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您好,我有一个简单的问题。我在下面有这段代码,我以非常相似的方式使用了 ajax 三次,唯一改变的是传递的数据和目标的 id。有没有办法将这些指令组合成一个简单的指令?谢谢D.

$('#fld_email').focusout(function() {
var request_email = $(this).val();
$.ajax({type:"GET",
url: "autocomplete.asp",
data: "fld=firstname&email="+request_email,
beforeSend: function(){$('#fld_firstname').addClass('ac_loading');},
success: function(msg){$('#fld_firstname').val(msg);$('#fld_firstname').removeClass('ac_loading'); }
});
$.ajax({type:"GET",
url: "autocomplete.asp",
data: "fld=lastname&email="+request_email,
beforeSend: function(){$('#fld_lastname').addClass('ac_loading');},
success: function(msg){$('#fld_lastname').val(msg);$('#fld_lastname').removeClass('ac_loading');}
});
$.ajax({type:"GET",
url: "autocomplete.asp",
data: "fld=phone&email="+request_email,
beforeSend: function(){$('#fld_phone').addClass('ac_loading');},
success: function(msg){$('#fld_phone').val(msg);$('#fld_phone').removeClass('ac_loading');}
});
}
);

最佳答案

尝试:

$('#fld_email').focusout(function() {
var request_email = $(this).val();
processAjax("fld=firstname&email="+request_email, '#fld_firstname');
processAjax("fld=lastname&email="+request_email, '#fld_lastname');
processAjax("fld=phone&email="+request_email, '#fld_phone');
});

function processAjax(data, id){
$.ajax({type:"GET",
url: "autocomplete.asp",
data: data,
beforeSend: function(){$(id).addClass('ac_loading');},
success: function(msg){$(id).val(msg).removeClass('ac_loading');}
});
}

关于javascript - 如何在 jquery 中对规则进行分组,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/2903088/

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