java - 带有 LIKE 和 IgnoreCase 的 Spring Data CrudRepository @Query

Question

我需要从 CrudRepository 中检索一些实体字段:

public class User {
    private String name;

    // getters and setters
}

public interface UserRepository extends CrudRepository<User, Long> { 

   @Query("SELECT U.name FROM User U WHERE LOWER(U.name) LIKE LOWER(?1)")
   List<String> findByName(String matchPhrase);
}

基本上，我想获得等效的 SQL 查询:

SELECT u.name FROM user u WHERE LOWER(u.name) LIKE LOWER('match%')

问题是@Query 不起作用(返回空列表)，hibernate 生成日志:

Hibernate: select user0_.name as col_0_0_ from user user0_ where lower(user0_.name) like lower(?)

我实际上并不知道如何指定一个附加了 % 的参数。

// also fails at compile-time
@Query("SELECT U.name FROM User U WHERE LOWER(U.name) LIKE LOWER(?1%)")

org.hibernate.hql.internal.ast.QuerySyntaxException: unexpected token: null near line ...

这工作正常但返回整个实体，这可能会产生很长的响应，因为我只需要检索特定字段:

List<User> findByNameStartingWithIgnoreCase(String match);

Answer 1

试试这个

@Query("SELECT U.name FROM User U WHERE LOWER(U.name) LIKE LOWER(concat(?1, '%'))")
List<String> findByName(String matchPhrase);