java - "java.lang.IllegalArgumentException: Parameter with that position [1] did not exist"当我使用spring-data-jpa

Question

我正在使用 spring-data-jpa+hibernate。1.我遇到以下异常……

Caused by: java.lang.IllegalArgumentException: Parameter with that position [1] did not exist
    at org.hibernate.jpa.spi.BaseQueryImpl.findParameterRegistration(BaseQueryImpl.java:518) ~[BaseQueryImpl.class:4.3.7.Final]
    at org.hibernate.jpa.spi.BaseQueryImpl.setParameter(BaseQueryImpl.java:674) ~[BaseQueryImpl.class:4.3.7.Final]
    at org.hibernate.jpa.spi.AbstractQueryImpl.setParameter(AbstractQueryImpl.java:198) ~[AbstractQueryImpl.class:4.3.7.Final]
    at org.hibernate.jpa.spi.AbstractQueryImpl.setParameter(AbstractQueryImpl.java:49) ~[AbstractQueryImpl.class:4.3.7.Final]
    at org.springframework.data.jpa.repository.query.ParameterBinder.bind(ParameterBinder.java:165) ~[ParameterBinder.class:?]
    at org.springframework.data.jpa.repository.query.StringQueryParameterBinder.bind(StringQueryParameterBinder.java:66) ~[StringQueryParameterBinder.class:?]

……

1. 我相信异常来自

   public interface FamousExperienceDao extends PagingAndSortingRepository<FamousExperience,
     Long>,JpaSpecificationExecutor<FamousExperience>
   {
       @Query( value = 
           "select new com.tujia.community.entity.BriefInfomation(f.id,f.title,f.summary,f.thumbnail,f.author, f.issueDate, f.counter) from FamousExperience f"
           ,countQuery ="select count(f.id) from FamousExperience f")
       public Page<BriefInfomation> findExps(Specification<FamousExperience> spec, Pageable pgbl);
   }
   

因为在我从函数 findExps 的参数中去掉 Specification spec 之后，它运行良好，我只想为查询添加规范。

BYW，FamousExperience 类扩展了 BriefInfomation。我使用了 JPA 查询的“构造函数表达式”功能，我只是在尝试查询时不需要属性“内容”。

@Entity
@Table(name = "famous_experience")
public class FamousExperience extends BriefInfomation
    {
    private String content;

    /**
     * @return the content
     */
    public String getContent()
    {
        return content;
    }

    /**
     * @param content the content to set
     */
    public void setContent(String content)
    {
        this.content = content;
    }
}

请帮帮我!

Answer 1

如果你在那里有规范规范，你将需要在你的查询中的某个地方引用它......重要的是，当你在那里有一个可分页时，计数器似乎不是从 ?0 开始，而是从 ?1

所以这样的事情应该可行

 @Query( value = 
    "from FamousExperience f where f.spec = ?1"
    ,countQuery ="select count(f.id) from FamousExperience f")