java - Drools DSL - 如何在规则中使用括号

Question

Drools 版本:6.3.0.Final

波乔:

public class Person {
    private Integer age;
    private Integer childrens;
    private String name;
    private String address;
    (...) 
}

DSL 文件:

[condition][]and=&&
[condition][]or=||
[condition][]is less than or equal to=<=
[condition][]is less than=<
[condition][]is greater than or equal to=>=
[condition][]is greater than=>
[condition][]is equal to===
[condition][]There is a [Pp]erson with=$person:Person()
[condition][].{field:\w*}  {operator}  {value:\d*}={field}  {operator}  {value}
(...)

DSRL 文件:

package <package>;

import <import class>.*

global org.slf4j.Logger logger;

expander <class>.dsl;

rule "R1"
    when
        There is a person with
        .age is greater than 10 or .chidldrens is less than 2 and .name is  equal to "<name>"
    then
        (...)
end 

rule "R2"
    when
        There is a person with
        (.age is greater than 10 or .childrens is less than 2) and .name is equal to "<name>"
    then
        (...)
end 

DRL(来自 R1):

(...)
rule "R1"
        when
            $person:Person(age > 10 || childrens < 2 && name = "<name>")
        then
            (...)
    end 
(...)

DRL(来自 R2):没有生成规则。

如果我删除括号，它可以正常工作，但如果有括号，则 DRL 文件无法正确生成。所以只有 R2 规则有效，但我的目标是 R1 规则。

有什么想法吗？

Answer 1

我想我找到了一个可能的解决方案:

DSL 文件(用这个新条件替换):

[condition][]There is a [Pp]erson that {constraints}=$person:Person({constraints})
[condition][]{field:\w*}\s+{operator}\s+{value:\s*}={field}  {operator}  {value}

DSRL(从第一行开始定义约束):

(...)
There is a person that ((age is greater than 10 or chidldrens is less than 2) and name is equal to "<name>")
(...)

DRL(生成):

(...)
$person:Person((age > 10 || childrens < 2) && name == "name")
(...)

使用这个新的 DSL 定义括号是受支持的，它按预期工作。你怎么看@laune？