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java - Java 7 异步 NIO2 服务器上的连接被拒绝

转载 作者:搜寻专家 更新时间:2023-11-01 02:50:00 25 4
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我使用 java 7 nio2 编写了一个异步套接字服务器。

这是服务器的截图。

public class AsyncJava7Server implements Runnable, CounterProtocol, CounterServer{
private int port = 0;
private AsynchronousChannelGroup group;
public AsyncJava7Server(int port) throws IOException, InterruptedException, ExecutionException {
this.port = port;
}

public void run() {
try {
String localhostname = java.net.InetAddress.getLocalHost().getHostName();
group = AsynchronousChannelGroup.withThreadPool(
Executors.newCachedThreadPool(new NamedThreadFactory("Channel_Group_Thread")));

// open a server channel and bind to a free address, then accept a connection
final AsynchronousServerSocketChannel asyncServerSocketChannel =
AsynchronousServerSocketChannel.open(group).bind(
new InetSocketAddress(localhostname, port));

asyncServerSocketChannel.accept(null,
new CompletionHandler <AsynchronousSocketChannel, Object>() {
@Override
public void completed(final AsynchronousSocketChannel asyncSocketChannel,
Object attachment) {
// Invoke simple handle accept code - only takes about 10 milliseconds.
handleAccept(asyncSocketChannel);
asyncServerSocketChannel.accept(null, this);
}
@Override
public void failed(Throwable exc, Object attachment) {
System.out.println("***********" + exc + " statement=" + attachment);
}
});

这是尝试连接的客户端代码片段...

public class AsyncJava7Client implements CounterProtocol, CounterClientBridge {
AsynchronousSocketChannel asyncSocketChannel;

private String serverName= null;
private int port;
private String clientName;

public AsyncJava7Client(String clientName, String serverName, int port) throws IOException {
this.clientName = clientName;
this.serverName = serverName;
this.port = port;
}

private void connectToServer() {
Future<Void> connectFuture = null;
try {
log("Opening client async channel...");
asyncSocketChannel = AsynchronousSocketChannel.open();

// Connecting to server
connectFuture = asyncSocketChannel.connect(new InetSocketAddress("Alex-PC", 9999));
} catch (Exception ex) {
ex.printStackTrace();
throw new RuntimeException(ex);
}
// open a new socket channel and connect to the server
long beginTime = 0;
try {
// You have two seconds to connect. This will throw exception if server is not there.
beginTime = System.currentTimeMillis();
Void connectVoid = connectFuture.get(15, TimeUnit.SECONDS);
} catch (Exception ex) {
//EXCEPTIONS THROWN HERE AFTER ABOUT 150 CLIENTS
long endTime = System.currentTimeMillis();
long timeTaken = endTime - beginTime;
log("************* TIME TAKEN=" + timeTaken);
ex.printStackTrace();
throw new RuntimeException(ex);
}
}

我有一个触发客户的测试。

 @Test
public void testManyClientsAtSametime() throws Exception {
int clientsize = 150;
ScheduledThreadPoolExecutor executor =
(ScheduledThreadPoolExecutor) Executors.newScheduledThreadPool(clientsize + 1,
new NamedThreadFactory("Test_Thread"));
AsyncJava7Server asyncJava7Server = startServer();
List<AsyncJava7Client> clients = new ArrayList<AsyncJava7Client>();
List<Future<String>> results = new ArrayList<Future<String>>();

for (int i = 0; i < clientsize; i++) {
// Now start a client
final AsyncJava7Client client =
new AsyncJava7Client("client" + i, InetAddress.getLocalHost().getHostName(), 9999);
clients.add(client);
}

long beginTime = System.currentTimeMillis();
Random random = new Random();
for (final AsyncJava7Client client: clients) {
Callable<String> callable = new Callable<String>() {
public String call() {
...
... invoke APIs to connect client to server
...
return counterValue;
}
};

long delay = random.nextLong() % 10000; // somewhere between 0 and 10 seconds.
Future<String> startClientFuture = executor.schedule(callable, delay, TimeUnit.MILLISECONDS);
results.add(startClientFuture);
}

它对大约 100 个客户非常有效。在大约 140+ 时,客户端出现大量异常 - 当它尝试连接时。异常是:java.util.concurrent.ExecutionException:java.io.IOException:远程计算机拒绝网络连接。

我的测试是在一台运行 Windows 7 的笔记本电脑上进行的。当它崩溃时,我检查了 TCP 连接,发现大约有 500 - 600 个连接 - 没问题。因为我有类似的 JDK 1.0 java.net 套接字程序,可以处理 4,000 个 TCP 连接。

在服务器中没有异常或任何可疑的东西。

所以我不知道这里可能出了什么问题。有什么想法吗?

最佳答案

尝试使用 bind 的形式接受积压限制并将其设置为更高的数字。例如:

            final AsynchronousServerSocketChannel asyncServerSocketChannel =
AsynchronousServerSocketChannel.open(group).bind(
new InetSocketAddress(localhostname, port), 1000);

我不知道默认情况下 win7 实现限制是什么,但可能是拒绝连接的原因。

关于java - Java 7 异步 NIO2 服务器上的连接被拒绝,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/13085070/

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