java - @TableGenerator : how to use

Question

我将尝试使用表生成器生成主键。但是当我在我的表中插入 6 条记录时，primaryKey 表只显示一个值。这是下面的代码

我的实体类

package com.generatorvaluetest.domain;

import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.SequenceGenerator;
import javax.persistence.TableGenerator;

@Entity
public class Snufu {
private int autoId;
private int identityId;
private int sequenceId;
private int tableId;
private String name;
public int getAutoId() {
    return autoId;
}
public void setAutoId(int autoId) {
    this.autoId = autoId;
}
public int getIdentityId() {
    return identityId;
}
public void setIdentityId(int identityId) {
    this.identityId = identityId;
}
public int getSequenceId() {
    return sequenceId;
}
public void setSequenceId(int sequenceId) {
    this.sequenceId = sequenceId;
}

@Id
@TableGenerator(name="tg" , table="pk_table", pkColumnName="name" , 
valueColumnName="vlaue" , allocationSize=10)
@GeneratedValue(strategy=GenerationType.TABLE , generator="tg")
public int getTableId() {
    return tableId;
}
public void setTableId(int tableId) {
    this.tableId = tableId;
}

public String getName() {
    return name;
}
public void setName(String name) {
    this.name = name;
}
  }

这是我的主课

 package com.generatorvaluetest.main;

 import org.hibernate.HibernateException;
 import org.hibernate.Session;

 import com.generatorvaluetest.domain.Snufu;
 import com.generatorvaluetest.util.HibernateUtil;

 public class GeneratorValueTest {
public static void main(String[] args) throws HibernateException{
    HibernateUtil.recreateDatabase();
    Session session = HibernateUtil.beginTransaction();
    for(int i = 0 ; i< 5 ; i++){
        Snufu snufu = new Snufu();
        snufu.setName("jimmy"+i);
        session.saveOrUpdate(snufu);
    }

    new Thread(new Runnable() {

        @Override
        public void run() {
            Session session = HibernateUtil.beginTransaction();
            Snufu snufu = new Snufu();
            snufu.setName("jimmykalra");
            session.saveOrUpdate(snufu);
            HibernateUtil.commitTransaction();
        }
    }).start();
    HibernateUtil.commitTransaction();
}
  }

在数据库中，当我从 pk_table 中选择值时，这些值是

|name | value|
|snuf | 1    |

但是在snufu表中有6条记录

Answer 1

与指定的表相比，valueColumnName 的值拼写错误。也没有提到要引用哪一行来获取键，由列值(pkColumnValue)标识。

下面是示例代码&可以引用TableGenerator documentation , 供进一步引用。

TableGenerator(name="tg" , table="pk_table", pkColumnName="value" , 
valueColumnName="name" , pkColumnValue = "snuf", allocationSize=10)