java - 打印字母的for循环

Question

public class LetterPrint {
    int totalLines;
    int consecLines;
    int timesPrintedinLine;
    int linesPrinted;
    char currentChar;
    LetterPrint(int totalLines, int consecLines){
        this.totalLines = totalLines;
        this.consecLines = consecLines;
    }
    void beginPrinting(){
        for(timesPrintedinLine = 0; linesPrinted<=totalLines; timesPrintedinLine++)
        {
            Print();
        }
    }
    public char correctChar(){
        if(timesPrintedinLine/(consecLines*4) == 1)
            return currentChar = 'A';
        else 
            return currentChar = 'B';

    }
    void Print(){
        if (timesPrintedinLine%5 !=0)
            System.out.print(correctChar());
        else{
            System.out.println();
            linesPrinted = timesPrintedinLine/4;
        }

    }
}

谁能帮我看看为什么，当用“LetterPrint letterPrinter = new LetterPrint(6,1);”创建时这个对象正在打印

BBBA
AABB
BBBB
BBBB
BBBB
BBBB 

而不是

AAAA
BBBB
AAAA
BBBB
AAAA
BBBB

我感谢任何能为我解决这个问题的人。

Answer 1

好吧，因为原始代码不是“最好的”，所以我重写了它:

public class LetterPrint
{
    private final static int charsInLine = 4;

    private final int totalLines;
    private final int consecLines;

    public LetterPrint(int totalLines, int consecLines)
    {
        this.totalLines = totalLines;
        this.consecLines = consecLines;
    }

    public void beginPrinting()
    {
        for (int lineNumber = 0; lineNumber < totalLines; lineNumber++)
        {
            char currentChar = getChar(lineNumber);
            for (int charNumber = 0; charNumber < charsInLine; charNumber++)
            {
                System.out.print(currentChar);
            }
            System.out.println();
        }
    }

    private char getChar(int lineNumber)
    {
        if ((lineNumber / consecLines) % 2 == 0)
        {
            return 'A';
        }
        return 'B';
    }
}