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java - 是否可以强制 JButton 始终为正方形?

转载 作者:搜寻专家 更新时间:2023-11-01 01:54:22 26 4
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我正在编写一个扫雷克隆程序,我现在遇到的问题是网格上按钮的比例 - 我想允许用户随意调整窗口大小,但我希望按钮保持不变1:1 的宽度/高度比,而不是在某些情况下变成煎饼或 jail 酒吧:)有没有什么方法可以轻松地强制 JButton 始终保持方形而不给它固定的宽度和高度?

最佳答案

您可以编写自定义 LayoutManager 例如GridLayout 扩展并设置子项大小。

import javax.swing.*;
import java.awt.*;

public class SquareButtonsTestApp extends JFrame {

public static void main ( String[] args ) {
new SquareButtonsTestApp();
}

public SquareButtonsTestApp() {
setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
getContentPane().setLayout(new MyGridLayout(10, 20));
for (int i=0; i<10; i++) {
for (int j=0; j<20; j++) {
getContentPane().add(new JButton(" "));
}
}
setSize(800,600);
setLocationRelativeTo(null);
setVisible(true);
}

class MyGridLayout extends GridLayout {
public MyGridLayout(int rows, int cols) {
super(rows, cols);
}
public void layoutContainer(Container parent) {
synchronized (parent.getTreeLock()) {
Insets insets = parent.getInsets();
int ncomponents = parent.getComponentCount();
int nrows = getRows();
int ncols = getColumns();
boolean ltr = parent.getComponentOrientation().isLeftToRight();

if (ncomponents == 0) {
return;
}
if (nrows > 0) {
ncols = (ncomponents + nrows - 1) / nrows;
} else {
nrows = (ncomponents + ncols - 1) / ncols;
}
// 4370316. To position components in the center we should:
// 1. get an amount of extra space within Container
// 2. incorporate half of that value to the left/top position
// Note that we use trancating division for widthOnComponent
// The reminder goes to extraWidthAvailable
int totalGapsWidth = (ncols - 1) * getHgap();
int widthWOInsets = parent.getWidth() - (insets.left + insets.right);
int widthOnComponent = (widthWOInsets - totalGapsWidth) / ncols;
int extraWidthAvailable = (widthWOInsets - (widthOnComponent * ncols + totalGapsWidth)) / 2;

int totalGapsHeight = (nrows - 1) * getVgap();
int heightWOInsets = parent.getHeight() - (insets.top + insets.bottom);
int heightOnComponent = (heightWOInsets - totalGapsHeight) / nrows;
int extraHeightAvailable = (heightWOInsets - (heightOnComponent * nrows + totalGapsHeight)) / 2;

int size=Math.min(widthOnComponent, heightOnComponent);
widthOnComponent=size;
heightOnComponent=size;
if (ltr) {
for (int c = 0, x = insets.left + extraWidthAvailable; c < ncols ; c++, x += widthOnComponent + getHgap()) {
for (int r = 0, y = insets.top + extraHeightAvailable; r < nrows ; r++, y += heightOnComponent + getVgap()) {
int i = r * ncols + c;
if (i < ncomponents) {
parent.getComponent(i).setBounds(x, y, widthOnComponent, heightOnComponent);
}
}
}
} else {
for (int c = 0, x = (parent.getWidth() - insets.right - widthOnComponent) - extraWidthAvailable; c < ncols ; c++, x -= widthOnComponent + getHgap()) {
for (int r = 0, y = insets.top + extraHeightAvailable; r < nrows ; r++, y += heightOnComponent + getVgap()) {
int i = r * ncols + c;
if (i < ncomponents) {
parent.getComponent(i).setBounds(x, y, widthOnComponent, heightOnComponent);
}
}
}
}
}
}
}
}

关于java - 是否可以强制 JButton 始终为正方形?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/14379781/

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