java - HttpClient 检查 Kerberos 安全网页。 NTLM 登录无效

Question

我必须编写一个程序来检查我们公司的 Kerberos 安全站点。我尝试使用 HttpClient 并收到以下错误:

KrbException: Server not found in Kerberos database (7)
    at sun.security.krb5.KrbTgsRep.<init>(KrbTgsRep.java:61)
    at sun.security.krb5.KrbTgsReq.getReply(KrbTgsReq.java:185)
        ...

我在 5 个月前写了一个 NTLM 登录，但它不适用于这个 Kerberos 安全站点。我认为 Nego2 已激活，因此如果 Kerberos 失败，它不会回退到 NTLM。

我阅读了 Kerberos 维基百科文章:http://en.wikipedia.org/wiki/Kerberos_(protocol)我认为问题是 TGS 在数据库中找不到请求的服务。我认为这是因为我在错误发生前收到了一张票(我认为是 TGT)。

Found ticket for userid@EXAMPLE.COM to go to krbtgt/EXAMPLE.COM@EXAMPLE.COM expiring on Thu May 31 01:35:56 CEST 2012

所以错误会发生在“客户端服务授权” --> 2.(参见维基百科文章)

问题是该服务必须在 kerberos 数据库中，因为我可以使用 IE 访问它(无需登录，因此单点登录有效)。

所以我的问题是:为什么 TGS 在 Kerberos 数据库中找不到服务器，但它可以与 IE 一起使用？

额外信息
我试图在顶部获取必要的信息，但这里是所有信息，因为我不知道我是否获得了所有必要的信息:

操作系统是Windows 7
Firefox 版本 9.0.1
Chrome 版本 19.0.1084.52
Safari 版本 5.0.2
浏览器版本 8.0.7600.16385

我的 Java 代码:

    System.setProperty("java.security.auth.login.config", "file://c:/temp/jaas.conf");
    System.setProperty("java.security.krb5.conf", "c:/winnt/krb5.ini");
    System.setProperty("sun.security.krb5.debug", "true");
    System.setProperty("javax.security.auth.useSubjectCredsOnly","false");

    DefaultHttpClient httpclient = new DefaultHttpClient();
    try {
        httpclient.getAuthSchemes().register(AuthPolicy.SPNEGO, new SPNegoSchemeFactory());

        Credentials use_jaas_creds = new Credentials() {

            public String getPassword() {
                return null;
            }

            public Principal getUserPrincipal() {
                return null;
            }

        };

        httpclient.getCredentialsProvider().setCredentials(
                new AuthScope(null, -1, null),
                use_jaas_creds);

        HttpUriRequest request = new HttpGet("url.com:port/site"); //Kerberos secured url
        HttpResponse response = httpclient.execute(request);
        HttpEntity entity = response.getEntity();

        System.out.println("----------------------------------------");
        System.out.println(response.getStatusLine());
        System.out.println("----------------------------------------");
        if (entity != null) {
            System.out.println(EntityUtils.toString(entity));
        }
        System.out.println("----------------------------------------");

        // This ensures the connection gets released back to the manager
        EntityUtils.consume(entity);

jaas.conf

com.sun.security.jgss.login {
com.sun.security.auth.module.Krb5LoginModule required client=TRUE;
};
com.sun.security.jgss.initiate {
com.sun.security.auth.module.Krb5LoginModule required client=TRUE;
};
com.sun.security.jgss.accept {
com.sun.security.auth.module.Krb5LoginModule required client=TRUE;
};

krb5.ini

[logging]
 default = FILE:log/krb5libs.log
 kdc = FILE:log/krb5kdc.log
 admin_server = FILE:log/kadmind.log

[libdefaults]
 ticket_lifetime = 24000
 default_realm = EXAMPLE.COM
 dns_lookup_realm = false
 dns_lookup_kdc = false

[realms]
 EXAMPLE.COM = {
  kdc = url
  admin_server = url
 }

[domain_realm]
 url.com = EXAMPLE.COM

[kdc]
 profile = /var/kerberos/krb5kdc/kdc.conf

[appdefaults]
 pam = {
   debug = false
   ticket_lifetime = 36000
   renew_lifetime = 36000
   forwardable = true
   krb4_convert = false
 }

来自测试运行的孔日志文件:

log4j:WARN No appenders could be found for logger (org.apache.http.impl.conn.BasicClientConnectionManager).
log4j:WARN Please initialize the log4j system properly.
Kerberos-Benutzername [user]: user
Kerberos-Passwort für user: *******
Using builtin default etypes for default_tkt_enctypes
default etypes for default_tkt_enctypes: 3 1 23 16 17.
Using builtin default etypes for default_tkt_enctypes
default etypes for default_tkt_enctypes: 3 1 23 16 17.
>>> KrbAsReq calling createMessage
>>> KrbAsReq in createMessage
>>> KrbKdcReq send: kdc=kdcurl UDP:88, timeout=30000, number of retries =3, #bytes=155
>>> KDCCommunication: kdc=kdcurl UDP:88, timeout=30000,Attempt =1, #bytes=155
>>> KrbKdcReq send: #bytes read=220
>>> KrbKdcReq send: #bytes read=220
>>> KDCRep: init() encoding tag is 126 req type is 11
>>>KRBError:
     sTime is Thu May 31 08:46:29 CEST 2012 1338446789000
     suSec is 51983
     error code is 25
     error Message is Additional pre-authentication required
     realm is EXAMPLE.COM
     sname is krbtgt/EXAMPLE.COM
     eData provided.
     msgType is 30
>>>Pre-Authentication Data:
     PA-DATA type = 11
     PA-ETYPE-INFO etype = 23
>>>Pre-Authentication Data:
     PA-DATA type = 2
     PA-ENC-TIMESTAMP
>>>Pre-Authentication Data:
     PA-DATA type = 15
AcquireTGT: PREAUTH FAILED/REQUIRED, re-send AS-REQ
Using builtin default etypes for default_tkt_enctypes
default etypes for default_tkt_enctypes: 3 1 23 16 17.
Pre-Authentication: Set preferred etype = 23
>>>KrbAsReq salt is EXAMPLE.COMuser
Pre-Authenticaton: find key for etype = 23
AS-REQ: Add PA_ENC_TIMESTAMP now
>>> EType: sun.security.krb5.internal.crypto.ArcFourHmacEType
>>> KrbAsReq calling createMessage
>>> KrbAsReq in createMessage
>>> KrbKdcReq send: kdc=kdcurl UDP:88, timeout=30000, number of retries =3, #bytes=219
>>> KDCCommunication: kdc=kdcurl UDP:88, timeout=30000,Attempt =1, #bytes=219
>>> KrbKdcReq send: #bytes read=100
>>> KrbKdcReq send: #bytes read=100
>>> KDCRep: init() encoding tag is 126 req type is 11
>>>KRBError:
     sTime is Thu May 31 08:46:29 CEST 2012 1338446789000
     suSec is 114485
     error code is 52
     error Message is Response too big for UDP, retry with TCP
     realm is EXAMPLE.COM
     sname is krbtgt/EXAMPLE.COM
     msgType is 30
>>> KrbKdcReq send: kdc=kdcurl TCP:88, timeout=30000, number of retries =3, #bytes=219
>>>DEBUG: TCPClient reading 3277 bytes
>>> KrbKdcReq send: #bytes read=3277
>>> KrbKdcReq send: #bytes read=3277
>>> EType: sun.security.krb5.internal.crypto.ArcFourHmacEType
>>> KrbAsRep cons in KrbAsReq.getReply user
Using builtin default etypes for default_tkt_enctypes
default etypes for default_tkt_enctypes: 3 1 23 16 17.
Found ticket for user@EXAMPLE.COM to go to krbtgt/EXAMPLE.COM@EXAMPLE.COM expiring on Thu May 31 18:46:29 CEST 2012
Entered Krb5Context.initSecContext with state=STATE_NEW
Service ticket not found in the subject
>>> Credentials acquireServiceCreds: same realm
Using builtin default etypes for default_tgs_enctypes
default etypes for default_tgs_enctypes: 3 1 23 16 17.
>>> CksumType: sun.security.krb5.internal.crypto.RsaMd5CksumType
>>> EType: sun.security.krb5.internal.crypto.ArcFourHmacEType
>>> KrbKdcReq send: kdc=kdcurl UDP:88, timeout=30000, number of retries =3, #bytes=3298
>>> KDCCommunication: kdc=kdcurl UDP:88, timeout=30000,Attempt =1, #bytes=3298
>>> KrbKdcReq send: #bytes read=110
>>> KrbKdcReq send: #bytes read=110
>>> KDCRep: init() encoding tag is 126 req type is 13
>>>KRBError:
     sTime is Thu May 31 08:46:29 CEST 2012 1338446789000
     suSec is 192613
     error code is 7
     error Message is Server not found in Kerberos database
     realm is EXAMPLE.COM
     sname is HTTP/url.com:port
     msgType is 30
KrbException: Server not found in Kerberos database (7)
    at sun.security.krb5.KrbTgsRep.<init>(KrbTgsRep.java:61)
    at sun.security.krb5.KrbTgsReq.getReply(KrbTgsReq.java:185)
    at sun.security.krb5.internal.CredentialsUtil.serviceCreds(CredentialsUtil.java:294)
    at sun.security.krb5.internal.CredentialsUtil.acquireServiceCreds(CredentialsUtil.java:106)
    at sun.security.krb5.Credentials.acquireServiceCreds(Credentials.java:562)
    at sun.security.jgss.krb5.Krb5Context.initSecContext(Krb5Context.java:594)
    at sun.security.jgss.GSSContextImpl.initSecContext(GSSContextImpl.java:230)
    at sun.security.jgss.GSSContextImpl.initSecContext(GSSContextImpl.java:162)
    at sun.security.jgss.spnego.SpNegoContext.GSS_initSecContext(SpNegoContext.java:851)
    at sun.security.jgss.spnego.SpNegoContext.initSecContext(SpNegoContext.java:309)
    at sun.security.jgss.GSSContextImpl.initSecContext(GSSContextImpl.java:230)
    at sun.security.jgss.GSSContextImpl.initSecContext(GSSContextImpl.java:162)
    at org.apache.http.impl.auth.GGSSchemeBase.generateGSSToken(GGSSchemeBase.java:99)
    at org.apache.http.impl.auth.SPNegoScheme.generateToken(SPNegoScheme.java:80)
    at org.apache.http.impl.auth.GGSSchemeBase.authenticate(GGSSchemeBase.java:155)
    at org.apache.http.impl.auth.SPNegoScheme.authenticate(SPNegoScheme.java:75)
    at org.apache.http.client.protocol.RequestAuthenticationBase.authenticate(RequestAuthenticationBase.java:125)
    at org.apache.http.client.protocol.RequestAuthenticationBase.process(RequestAuthenticationBase.java:83)
    at org.apache.http.client.protocol.RequestTargetAuthentication.process(RequestTargetAuthentication.java:80)
    at org.apache.http.protocol.ImmutableHttpProcessor.process(ImmutableHttpProcessor.java:109)
    at org.apache.http.protocol.HttpRequestExecutor.preProcess(HttpRequestExecutor.java:176)
    at org.apache.http.impl.client.DefaultRequestDirector.execute(DefaultRequestDirector.java:516)
    at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:906)
    at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:805)
    at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:784)
    at mypackage.ClientKerberosAuthentication.main(ClientKerberosAuthentication.java:152)
Caused by: KrbException: Identifier doesn't match expected value (906)
    at sun.security.krb5.internal.KDCRep.init(KDCRep.java:133)
    at sun.security.krb5.internal.TGSRep.init(TGSRep.java:58)
    at sun.security.krb5.internal.TGSRep.<init>(TGSRep.java:53)
    at sun.security.krb5.KrbTgsRep.<init>(KrbTgsRep.java:46)
    ... 25 more
----------------------------------------
HTTP/1.1 401 Unauthorized
----------------------------------------
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Draft//EN">
<HTML>
<HEAD>
<TITLE>Error 401--Unauthorized</TITLE>
</HEAD>
<BODY bgcolor="white">
<FONT FACE=Helvetica><BR CLEAR=all>
<TABLE border=0 cellspacing=5><TR><TD><BR CLEAR=all>
<FONT FACE="Helvetica" COLOR="black" SIZE="3"><H2>Error 401--Unauthorized</H2>
</FONT></TD></TR>
</TABLE>
<TABLE border=0 width=100% cellpadding=10><TR><TD VALIGN=top WIDTH=100% BGCOLOR=white><FONT FACE="Courier New"><FONT FACE="Helvetica" SIZE="3"><H3>From RFC 2068 <i>Hypertext Transfer Protocol -- HTTP/1.1</i>:</H3>
</FONT><FONT FACE="Helvetica" SIZE="3"><H4>10.4.2 401 Unauthorized</H4>
</FONT><P><FONT FACE="Courier New">The request requires user authentication. The response MUST include a WWW-Authenticate header field (section 14.46) containing a challenge applicable to the requested resource. The client MAY repeat the request with a suitable Authorization header field (section 14.8). If the request already included Authorization credentials, then the 401 response indicates that authorization has been refused for those credentials. If the 401 response contains the same challenge as the prior response, and the user agent has already attempted authentication at least once, then the user SHOULD be presented the entity that was given in the response, since that entity MAY include relevant diagnostic information. HTTP access authentication is explained in section 11.</FONT></P>
</FONT></TD></TR>
</TABLE>

</BODY>
</HTML>

----------------------------------------

Answer 1

这是行不通的。

1. Active Directory 不使用 SPN 中的任何端口。不知道 HttpClient 中那些愚蠢的东西是从哪里来的。
2. 在您的 Active Directory 中没有为您的目标主机注册 SPN。

问题的答案:

1. 一点也不，只有service class and hostname are mandatory .服务类已经标识了端口注册的服务，例如LDAP、HTTP、FTP 等。我们的森林中有数十万个 SPN。他们都没有端口。例如，我会做大量的工作来注册 HTTP 服务器的每个端口实例。AD 必须只知道目标主机。它将相应地加密服务票据。这使它独一无二。
2. 为什么浏览器会失败？它确实将 SPN 构建为 HTTP/<FQDN> .只要目录中有这个，一切都会很顺利。

当我尝试使用 HTTPClient 时，我对糟糕的 SPNEGO 支持一直不满意。当我动手时，我想重写那些东西。