java - Jackson 和 java.sql.Time 序列化/反序列化

Question

在 Hibernate 管理的实体中考虑这个属性:

@JsonFormat(pattern = "HH:mm")
@Column(name = "start_time")
private java.sql.Time startTime;

我将 JSON 对象作为 @RequestBody 发布到 Spring Controller，Jackson 应该映射到实体的实例( pojo).

Jackson 显然无法将时间字符串反序列化为 java.sql.Time，因为我得到了这个异常:

.w.s.m.s.DefaultHandlerExceptionResolver : Failed to read HTTP message:
org.springframework.http.converter.HttpMessageNotReadableException:
Could not read document: Can not construct instance of java.sql.Time,
problem: null

我如何指示 Jackson 了解该做什么？

Answer 1

解决方案是推出自己的反序列化器:

import java.io.IOException;
import java.sql.Time;
import com.fasterxml.jackson.core.JsonParser;
import com.fasterxml.jackson.databind.DeserializationContext;
import com.fasterxml.jackson.databind.JsonDeserializer;

public class SqlTimeDeserializer extends JsonDeserializer<Time> {

    @Override
    public Time deserialize(JsonParser jp, DeserializationContext ctxt) throws IOException {
        return Time.valueOf(jp.getValueAsString() + ":00");
    }
}

然后在实体中:

@JsonFormat(pattern = "HH:mm")
@JsonDeserialize(using = SqlTimeDeserializer.class)
@Column(name = "start_time")
private Time                startTime;