java - 如何读取内容编码为 : gzip 的压缩 HTML 页面

Question

我请求发送一个 Content-Encoding: gzip header 的网页，但无法阅读它..

我的代码:

    try {
        URLConnection connection = new URL("http://jquery.org").openConnection();                        
        String html = "";
        BufferedReader in = null;
        connection.setReadTimeout(10000);
    in = new BufferedReader(new InputStreamReader(connection.getInputStream()));            
    String inputLine;
    while ((inputLine = in.readLine()) != null){
    html+=inputLine+"\n";
        }
    in.close();
        System.out.println(html);
        System.exit(0);
    } catch (IOException ex) {
        Logger.getLogger(Crawler.class.getName()).log(Level.SEVERE, null, ex);
    }

输出看起来很乱..(我无法在这里粘贴它，一种符号..)

我认为这是一个压缩内容，如何解析它？

注意:
如果我将 jquery.org 更改为 jquery.com(它不发送该 header ，我的代码运行良好)

Answer 1

实际上，这是 pb2q 的答案，但我将完整代码发布给 future 的读者

try {
    URLConnection connection = new URL("http://jquery.org").openConnection();                        
    String html = "";
    BufferedReader in = null;
    connection.setReadTimeout(10000);
    //The changed part
    if (connection.getHeaderField("Content-Encoding")!=null && connection.getHeaderField("Content-Encoding").equals("gzip")){
        in = new BufferedReader(new InputStreamReader(new GZIPInputStream(connection.getInputStream())));            
    } else {
        in = new BufferedReader(new InputStreamReader(connection.getInputStream()));            
    }     
    //End        
    String inputLine;
    while ((inputLine = in.readLine()) != null){
    html+=inputLine+"\n";
    }
in.close();
    System.out.println(html);
    System.exit(0);
} catch (IOException ex) {
    Logger.getLogger(Crawler.class.getName()).log(Level.SEVERE, null, ex);
}