node.js - 动态生成的 Mocha 测试不在异步/等待上下文中执行

Question

我无法运行我的 Mocha 测试。我需要测试的部分内容是我以异步方式(从远程服务器)获取的，由我的 getStatus() 函数返回(为简单起见用超时替换)。我有一个没有 async/await 的类似代码示例，它工作正常(如果需要，也可以提供 repl.it)。

简化代码(你可以玩一下 here on repl.it ):

const sleep = require('util').promisify(setTimeout);

const getStatus = async function() {
    await sleep(1000);
    return 2;
};

describe('main describe', async function () {
    let uids = [1,2,3];

    describe('Tha test!', async function () {
        console.info('started describe() block...');

        let outcome;
        let status;

        const callback = function () {
            console.info(`inside callback, status is ${status} and outcome is ${outcome}`);
            expect(status).to.equal(outcome);
        };

        for(let uid in uids) {
            status = await getStatus(uids[uid]);
            console.info('the status returned by getStatus is:', status);
            it(`The status for ${uids[uid]} should be ${outcome}`, callback);
        }
    });
});

注意:it() 子句中的回调的灵感来自 this question .

输出:

started describe() block...

  0 passing (0ms)

the status returned by getStatus is: 2
the status returned by getStatus is: 2
the status returned by getStatus is: 2

预期输出:

started describe() block...

the status returned by getStatus is: 2
the status returned by getStatus is: 2
the status returned by getStatus is: 2

      1) number 0 should equal 2
      2) number 1 should equal 2
      ✓ number 2 should equal 2

  1 passing (11ms)
  2 failing

问题:为什么我的 it() 子句没有执行？

Answer 1

事实证明，您不能将 async 回调传递给 describe()。谁知道。

为了让所有的异步功能正常工作，应该怎么做:

describe('do not put async before the function keyword!', function () {
    uids = process.env.ENV_OBJECTS.split(',');

    let outcome;

    for(let uid in uids) {
        it('Can safely put async before the function here', async function() {
            outcome = await getOutcome(uid);
            // etc.
        });
    }
});