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html - 通过 HTML5 Canvas 加入圆到线

转载 作者:搜寻专家 更新时间:2023-10-31 23:12:05 24 4
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我试图通过线加入每个圆圈,我的最终代码做到了,但它有一些对齐问题,比如:

enter image description here

我用红色圆圈标记了一些连接部分。如您所见,它们没有正确对齐(线没有从圆心出来)。

<!DOCTYPE HTML>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
</head>
<body>
<canvas id="graph" width="982" height="636" style="width:491px">
Tarayıcınız Canvas Desteklemiyor !
</canvas>

<script type="text/javascript">
var i = 0;
var lastCoord = new Array();
var c=document.getElementById("graph");
var cxt=c.getContext("2d");

function getParam(name)
{
name = name.replace(/[\[]/, "\\\[").replace(/[\]]/, "\\\]");
var regexS = "[\\?&]" + name + "=([^&#]*)";
var regex = new RegExp(regexS);
var results = regex.exec(window.location.href);
if(results == null)
return "";
else
return decodeURIComponent(results[1].replace(/\+/g, " "));
}

function drawCircleAndLine(x, y)
{
cxt.fillStyle="#000000";
cxt.beginPath();

if(i == 0) cxt.arc(x, y, 9, 0, Math.PI*2, false);
else cxt.arc(x, y, 6, 0, Math.PI*2, false);

cxt.closePath();
cxt.fill();

if(i % 4 != 0)
{
cxt.lineWidth = 8;

cxt.lineTo(lastCoord[0], lastCoord[1]);
cxt.stroke();
}
else {
cxt.moveTo(lastCoord[0], lastCoord[1]);
cxt.lineTo(lastCoord[0], lastCoord[1]);
cxt.stroke();
}

lastCoord = [x, y];
i++;

}

var coords = {
0 : {
0 : {
"0" : { "x" : 50, "y" : 580},
"1" : { "x" : 50, "y" : 540},
"2" : { "x" : 50, "y" : 472},
"3" : { "x" : 50, "y" : 430},
"4" : { "x" : 50, "y" : 400},
"5" : { "x" : 50, "y" : 382},
"6" : { "x" : 50, "y" : 340},
"7" : { "x" : 50, "y" : 300},
"8" : { "x" : 50, "y" : 250},
"9" : { "x" : 50, "y" : 205},
"10" : { "x" : 50, "y" : 160},
"12" : { "x" : 50, "y" : 138},
"14" : { "x" : 50, "y" : 110},
"15" : { "x" : 50, "y" : 85},
"16" : { "x" : 50, "y" : 65},
"20" : { "x" : 50, "y" : 40}
},

1 : {
"0" : { "x" : 98, "y" : 555},
"1" : { "x" : 98, "y" : 493},
"2" : { "x" : 98, "y" : 451},
..............
"-4" : { "x" : 926, "y" : 356},
"-5" : { "x" : 926, "y" : 375},
"-6" : { "x" : 926, "y" : 398},
"-7" : { "x" : 926, "y" : 428},
"-8" : { "x" : 926, "y" : 452},
"-9" : { "x" : 926, "y" : 476},
"-10" : { "x" : 926, "y" : 500},
"-11" : { "x" : 926, "y" : 530},
"-12" : { "x" : 926, "y" : 550},
"-16" : { "x" : 926, "y" : 588}
}
}
};

var bg = new Image();
bg.src = "images/disc_graph_empty.jpg";
bg.onload = function() {
cxt.drawImage(bg, 0, 0);

try
{
drawCircleAndLine(coords[0][0][getParam('d1')]["x"], coords[0][0][getParam('d1')]["y"]);
drawCircleAndLine(coords[0][2][getParam('d2')]["x"], coords[0][3][getParam('d2')]["y"]);
drawCircleAndLine(coords[0][2][getParam('d3')]["x"], coords[0][2][getParam('d3')]["y"]);
drawCircleAndLine(coords[0][3][getParam('d4')]["x"], coords[0][3][getParam('d4')]["y"]);

drawCircleAndLine(coords[1][0][getParam('d5')]["x"], coords[1][0][getParam('d5')]["y"]);
drawCircleAndLine(coords[1][4][getParam('d6')]["x"], coords[1][5][getParam('d6')]["y"]);
drawCircleAndLine(coords[1][2][getParam('d7')]["x"], coords[1][2][getParam('d7')]["y"]);
drawCircleAndLine(coords[1][3][getParam('d8')]["x"], coords[1][3][getParam('d8')]["y"]);

drawCircleAndLine(coords[2][0][getParam('d9')]["x"], coords[2][0][getParam('d9')]["y"]);
drawCircleAndLine(coords[2][6][getParam('d10')]["x"], coords[2][7][getParam('d10')]["y"]);
drawCircleAndLine(coords[2][2][getParam('d11')]["x"], coords[2][2][getParam('d11')]["y"]);
drawCircleAndLine(coords[2][3][getParam('d12')]["x"], coords[2][3][getParam('d12')]["y"]);
}
catch(err)
{
alert('Hata Oluştu !\nBazı noktalar yerleşmemiş olabilir.\n\n\n' + err);
}
}
</script>

</body>
</html>

所有文件:http://www.2shared.com/file/Uyh2J0Ni/canvas.html

最佳答案

这是对您的代码的主要简化,应该指出问题所在。我将填充设为浅蓝色并将笔划宽度变小,以便您可以看到问题所在。我只是调用了你的函数两次:

drawCircleAndLine(100,100);
drawCircleAndLine(100,200);

您会期望一条直线向下,但显然它不是直线!看这里:

http://jsfiddle.net/24khs/

这是怎么回事:

第一次,只绘制了一个圆心为 100,100 的圆。这个不错

第二次,在 200,200 处绘制了一个圆,然后该点的路径终点是圆的最右边部分(大约为 106,200)。然后,您将绘制一条从 (106,200) 到 (100,100) 的直线。

为了解决这个问题,您可以在 lineTo 之前添加一个命令,一个 moveTo(x, y),这样您就可以从正确的位置开始该行。看这里:

http://jsfiddle.net/6VfvG/

关于html - 通过 HTML5 Canvas 加入圆到线,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/7341630/

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