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swift - Swift 中的 localizeWithFormat 和可变参数

转载 作者:搜寻专家 更新时间:2023-10-31 22:35:51 24 4
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我正在尝试创建一个字符串扩展来做类似的事情

"My name is %@. I am %d years old".localizeWithFormat("John", 30)

看起来像这样

extension String {
func localizeWithFormat(arguments: CVarArgType...) -> String {
return String.localizedStringWithFormat(
NSLocalizedString(self,
comment: ""), getVaList(arguments))
}
}

它给我以下编译错误

Type CVaListPointer does not conform to protocol CVargType

有人知道如何解决这个编译错误吗?

最佳答案

这应该很简单,只需按如下方式更改参数即可:

extension String {
func localizeWithFormat(name:String,age:Int, comment:String = "") -> String {
return String.localizedStringWithFormat( NSLocalizedString(self, comment: comment), name, age)
}
}

"My name is %@. I am %d years old".localizeWithFormat("John", age: 30) // "My name is John. I am 30 years old"

init(format:locale:arguments:)

extension String {
func localizeWithFormat(args: CVarArgType...) -> String {
return String(format: self, locale: nil, arguments: args)
}
func localizeWithFormat(local:NSLocale?, args: CVarArgType...) -> String {
return String(format: self, locale: local, arguments: args)
}
}
let myTest1 = "My name is %@. I am %d years old".localizeWithFormat(NSLocale.currentLocale(), args: "John",30)
let myTest2 = "My name is %@. I am %d years old".localizeWithFormat("John",30)

关于swift - Swift 中的 localizeWithFormat 和可变参数,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/27914053/

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