'January',2=>'February',3=>'March',4=>'-6ren">
gpt4 book ai didi

php - 此代码的另一种方法是什么?

转载 作者:搜寻专家 更新时间:2023-10-31 22:05:25 24 4
gpt4 key购买 nike

我有以下代码。我有一个月的数组。

         $m="";
$months = array(1=>'January',2=>'February',3=>'March',4=>'April',5=>'May',6=>'June',7=>'July',8=>'August',9=>'September',10=>'October',11=>'November',12=>'December');

foreach($objhst_fees->fetch_hst_fees("`month`,`fees`","where `grno`='".$stu_name['grno']."'")as $count_month)
{
//value like:$count_month['month']=1,2,3
$m .= $count_month['month'].",";
}

所以假设 $m=1,2,3,4,5,
然后,我将其分解并创建数组。

          $paid_month = explode(",",$m);
$arr=array();
foreach($paid_month as $key=>$p)
{
array_push($arr,$p);
}

然后,我打印不在 $arr 中的月份名称。

          foreach($months as $key=>$a)
{
if(!in_array($key,$arr))
{
echo $a.",";
//echo $months[$key];
}
}

但我认为,这种方法很适合它。那么这样做的替代方案是什么?

最佳答案

在代码中:

foreach($objhst_fees->fetch_hst_fees("`month`,`fees`","where `grno`='".$stu_name['grno']."'")as $count_month) { 
//value like:$count_month['month']=1,2,3
$m .= $count_month['month'].",";
}

你可以改变:

$m  .= $count_month['month'].",";

$m[] = $count_month['month'];

这将避免再次对它进行 explode()

关于php - 此代码的另一种方法是什么?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/19515106/

24 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com