arrays - 使 Swift 数组语句更简洁

Question

我是编程新手，刚开始学习 Swift。对于我正在尝试解决的以下数组概念，您的帮助将不胜感激。

如何缩短下面的代码，以便减少 If 语句的数量。 So when a "battlename = name[0]"index is selected the statement automatically selects the corresponding monsters at the same index level without having to use so many If statements.

希望我说的有道理。

var names = ["Lancelot", "Arthur", "Gawain", "Galahad"]
var monsters = ["Dragon", "Boar", "Giant", "Griffin"]
let battlename = names[1]
print(battlename, "Vs.", monsters)

if battlename == names[0] {
print(battlename, "Vs.", monsters[0])
}
else if battlename == names[1] {
print(battlename, "Vs.", monsters[1])
}
else if battlename == names[2] {
print(battlename, "Vs.", monsters[2])
}
else if battlename == names[3] {
print(battlename, "Vs.", monsters[3])
}

Answer 1

您可以用这个条件替换所有条件:

if let index = names.indexOf(battlename) {
    print(battlename, "Vs.", monsters[index])
}

还有一个提示，如果你想在你的介绍中打印怪物名称列表，而不是仅仅打印数组，你可以将项目作为字符串连接:

print(battlename, "Vs.", monsters.joinWithSeparator(", ")) // "Arthur Vs. Dragon, Boar, Giant, Griffin"