php - 清除 SQLite3 语句上的绑定(bind)似乎不起作用 (PHP)

Question

当使用准备好的语句在 PHP 中向 SQLite3 插入多行时，如果您没有为一行绑定(bind)参数，那么将插入前一行的值，即使您“清除”了行与行之间的语句。

看下面的例子:

$db = new SQLite3('dogsDb.sqlite');

//create the database
$db->exec("CREATE TABLE Dogs (Id INTEGER PRIMARY KEY, Breed TEXT, Name TEXT, Age INTEGER)");    

$sth = $db->prepare("INSERT INTO Dogs (Breed, Name, Age)  VALUES (:breed,:name,:age)");

$sth->bindValue(':breed', 'canis', SQLITE3_TEXT);
$sth->bindValue(':name', 'jack', SQLITE3_TEXT);
$sth->bindValue(':age', 7, SQLITE3_INTEGER);
$sth->execute();

$sth->clear(); //this is supposed to clear bindings!
$sth->reset();

$sth->bindValue(':breed', 'russel', SQLITE3_TEXT);         
$sth->bindValue(':age', 3, SQLITE3_INTEGER);
$sth->execute();

尽管我希望第二行的“name”列具有 NULL 值，但该值是“jack”!

所以要么“清除”似乎不起作用(尽管它返回 true)，要么我还没有真正理解它应该做什么。

如何清除 SQLite3(甚至 PDO)中插入之间的绑定(bind)？在某些行的某些字段可能具有空值的情况下插入多行的最佳方法是什么？

Answer 1

#include <sqlite3.h>
#include <stdio.h>

int main(void) {

    sqlite3 *db;
    char *err_msg = 0;
    sqlite3_stmt *res;
    sqlite3_stmt *res1;
    int rc = sqlite3_open("test.sqlite", &db);

    if (rc != SQLITE_OK) {

        fprintf(stderr, "Cannot open database: %s\n", sqlite3_errmsg(db));
        sqlite3_close(db);

        return 1;
    }

    char *sql = "CREATE TABLE Dogs (Id INTEGER PRIMARY KEY, Breed TEXT, Name TEXT, Age TEXT)";
    rc = sqlite3_prepare_v2(db, sql, -1, &res, 0);
    if (rc == SQLITE_OK) {
        rc = sqlite3_step(res);

    }
    sqlite3_finalize(res);

    char *sql1 = "INSERT INTO Dogs (Breed, Name, Age)  VALUES (:breed,:name,:age);";

    rc = sqlite3_prepare_v2(db, sql1, -1, &res1, 0);


    if (rc == SQLITE_OK) {
        printf("%d\n", sqlite3_bind_text(res1, 1, "breed1", 6, SQLITE_STATIC));
        sqlite3_bind_text(res1, 2, "name1", 5, SQLITE_STATIC);
        sqlite3_bind_text(res1, 3, "age1", 4, SQLITE_STATIC);
        printf("%d\n", sqlite3_step(res1));
    } else {

        fprintf(stderr, "Failed to execute statement: %s\n", sqlite3_errmsg(db));
    }
    sqlite3_reset(res1);
    sqlite3_clear_bindings(res1);
    printf("%d\n", sqlite3_bind_text(res1, 2, "name2", 5, SQLITE_STATIC));
    printf("%d\n", sqlite3_bind_text(res1, 3, "age2", 4, SQLITE_STATIC));

    printf("%d\n", sqlite3_step(res1));


    sqlite3_finalize(res1);
    sqlite3_close(db);

    return 0;
}